Exoplanets
Planetary Equilibrium Temperature
The temperature a planet settles at when absorbed starlight balances the heat it radiates away
Planetary equilibrium temperature (T_eq) is the temperature a planet would reach if it were a bare, airless blackbody in perfect energy balance — absorbing exactly as much starlight as it radiates back to space as thermal infrared. It follows T_eq = T_star·√(R_star/2a)·(1−A)^¼, where T_star and R_star are the star's effective temperature and radius, a is the orbital semi-major axis, and A is the Bond albedo. For Earth (A ≈ 0.30) it comes out near 255 K — about 33 K below the observed 288 K mean surface temperature, a gap filled by the greenhouse effect. Because it needs only stellar parameters and orbital distance, it is computed for nearly every confirmed exoplanet as the first-order gauge of whether a world could be temperate.
- Governing lawT_eq = T_star·√(R_star/2a)·(1−A)^¼
- Earth (A = 0.30)≈ 255 K (−18 °C)
- Greenhouse offset+33 K → 288 K observed
- PhysicsStefan-Boltzmann radiative balance
- Planet radiusCancels out — irrelevant
- Dayside-only bonus×2^¼ ≈ +19% (no redistribution)
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Why equilibrium temperature matters
Equilibrium temperature is the single most-quoted number in exoplanet catalogs after mass and radius — and for good reason. It is the cheapest possible thermometer: it requires no spectrum, no atmospheric model, no phase curve, only the star's temperature and radius (from stellar characterization) and the planet's orbital distance (from the transit period plus Kepler's third law). With those in hand and one assumed albedo, you can estimate a temperature for a planet you have never resolved, orbiting a star hundreds of light-years away.
- Habitability triage. It defines the classical habitable zone — the orbital band where T_eq is consistent with liquid water given a plausible atmosphere. Worlds with T_eq of roughly 200–320 K get flagged for follow-up.
- Population sorting. Across the ~5,900 confirmed planets, T_eq cleanly separates lava worlds and hot Jupiters (>1000 K) from temperate rocky candidates.
- Atmospheric prediction. It tells you which volatiles can condense: below ~150 K water ice is stable; above ~1500 K silicates vaporize into rock-vapor atmospheres.
- The greenhouse yardstick. Comparing T_eq to a measured or modeled surface temperature quantifies greenhouse warming — 33 K for Earth, over 500 K for Venus.
- JWST target selection. Equilibrium temperature sets the expected thermal-emission brightness, driving which planets are worth precious secondary-eclipse time.
How it works, step by step
The whole idea is a balance sheet of power in versus power out. A planet in a steady state must radiate away exactly as much energy as it absorbs, or it would keep heating or cooling forever.
- Power in. The star radiates a luminosity L = 4πR_star²·σT_star⁴. At orbital distance a, that spreads over a sphere of area 4πa², giving a flux (the insolation) F = L / (4πa²). The planet intercepts this flux over its shadow — its cross-sectional disk of area πR_p² — and reflects a fraction A, so the absorbed power is P_in = (1−A)·F·πR_p².
- Power out. The planet re-radiates as a blackbody at temperature T_eq from its entire surface, area 4πR_p², so P_out = 4πR_p²·σT_eq⁴ (full redistribution over the whole globe).
- Set them equal. P_in = P_out. Every π and R_p² cancels — which is why the planet's size never appears in the answer.
- Solve for T_eq. Substituting L and simplifying gives the compact form below.
The governing equation
Starting from L = 4πR_star²σT_star⁴ and equating absorbed and emitted power, the algebra collapses to:
T_eq = T_star · √(R_star / 2a) · (1 − A)^¼
Equivalently, written directly from the incident flux F:
T_eq = [ (1 − A) · F / (4σ) ]^¼
| Symbol | Meaning | Units |
|---|---|---|
| T_eq | Planetary equilibrium temperature | K |
| T_star | Star's effective temperature | K |
| R_star | Stellar radius | m (or R_☉) |
| a | Orbital semi-major axis (star–planet distance) | m (or AU) |
| A | Bond albedo (fraction of all incident starlight reflected) | dimensionless, 0–1 |
| F | Incident stellar flux (insolation) at distance a | W/m² |
| σ | Stefan-Boltzmann constant (5.670×10⁻⁸) | W m⁻² K⁻⁴ |
Note the exponents. Distance enters as a−½, so doubling the orbital radius cools a planet by a factor of √2 ≈ 1.41. Albedo enters as (1−A)^¼, a deliberately gentle dependence: even a highly reflective world sheds only a modest fraction of its warmth. A generalized form multiplies by a redistribution factor f, where f = ¼ for full global redistribution (giving the standard formula) and f = ½ for dayside-only re-emission (raising T by 2^¼).
Worked example: why Earth should be frozen
Plug Earth's numbers into the flux form. The solar constant — the flux at 1 AU — is F ≈ 1361 W/m². Earth's Bond albedo is A ≈ 0.30. Then:
T_eq = [ (1 − 0.30) × 1361 / (4 × 5.670×10⁻⁸) ]^¼ ≈ 255 K (about −18 °C).
That is well below the freezing point of water. If Earth were the bare rock this calculation assumes, its oceans would be ice. The planet is habitable only because its atmosphere traps outgoing infrared: greenhouse gases raise the observed mean surface temperature to about 288 K (15 °C), a warming of 33 K. The same math with A = 0 (a perfectly black Earth) gives 278 K — a reminder of how weakly albedo pulls the result.
| Body | Bond albedo A | T_eq (K) | Actual mean surface (K) | Greenhouse offset |
|---|---|---|---|---|
| Mercury | 0.07 | ≈ 440 | ≈ 340 (mean); 700 dayside | none (no atmosphere) |
| Venus | 0.77 | ≈ 230 | 737 | +500 K (runaway) |
| Earth | 0.30 | ≈ 255 | 288 | +33 K |
| Mars | 0.25 | ≈ 210 | 210 | +5 K (thin CO₂) |
| Jupiter | 0.34 | ≈ 110 | 165 (1 bar) | internal heat |
| TRAPPIST-1 e | ~0.3 (assumed) | ≈ 250 | unknown | a JWST target |
Venus is the cautionary tale: its bright sulfuric-acid clouds reflect so much light that its equilibrium temperature (~230 K) is actually colder than Earth's, yet its dense CO₂ atmosphere drives a runaway greenhouse to 737 K — hotter than Mercury's dayside despite being nearly twice as far from the Sun. Equilibrium temperature and actual surface temperature can diverge by hundreds of kelvin.
Common misconceptions
- "Equilibrium temperature is the surface temperature." No — it is a bare-blackbody baseline. Real surfaces are warmed by greenhouse trapping (up) and cooled by high-albedo clouds (down); the two can shift the truth by hundreds of kelvin.
- "Bigger planets are warmer." The planet's radius cancels completely. A gas giant and a pebble at the same distance from the same star share the same T_eq.
- "A reflective planet is much colder." Albedo enters as (1−A)^¼, so it's a weak lever. Going from A = 0 to A = 0.3 cools Earth by only ~8 percent (278 K → 255 K).
- "It ignores the star's spectrum." Not quite — T_star and R_star fold in the star's full luminosity via Stefan-Boltzmann. What it ignores is wavelength-dependent absorption in a real atmosphere.
- "The dayside equals T_eq." Only under full heat redistribution. A tidally locked planet radiating from its dayside alone runs about 19 percent hotter at the substellar point (a factor of 2^¼).
- "Equilibrium temperature = a star's effective temperature." Same blackbody law, different power source: a star is heated from within, a planet from without.
A note on origins
The radiative-balance argument is old. Joseph Fourier reasoned in the 1820s that the Earth must be warmer than a bare sunlit rock, identifying atmospheric trapping as the cause — the first statement of what we now call the greenhouse effect. Svante Arrhenius quantified CO₂'s role in 1896. The compact blackbody equilibrium formula follows directly from Josef Stefan's 1879 empirical T⁴ law and Ludwig Boltzmann's 1884 derivation of it. In the exoplanet era, equilibrium temperature became a standard catalog column with the Kepler mission (launched 2009), which needed a uniform, model-light temperature to rank thousands of transiting candidates — the role it still plays across the NASA Exoplanet Archive today.
Frequently asked questions
What is a planet's equilibrium temperature?
It's the temperature a planet would settle at if it were a bare, airless blackbody in energy balance — absorbing exactly as much starlight as it radiates back to space as thermal infrared. It ignores atmospheres, internal heat, and greenhouse trapping. The governing formula is T_eq = T_star·√(R_star/2a)·(1−A)^¼, where T_star and R_star are the star's effective temperature and radius, a is the orbital semi-major axis, and A is the Bond albedo. It's a theoretical baseline, not a measured surface temperature.
Why is Earth's equilibrium temperature 255 K when it's actually warmer?
With a Bond albedo of about 0.30 and the Sun's flux at 1 AU, Earth's equilibrium temperature is roughly 255 K (−18 °C), which is below the freezing point of water. The observed global mean surface temperature is about 288 K (15 °C). The 33 K gap is the greenhouse effect: water vapor, CO2, and other gases absorb outgoing infrared and re-radiate it downward, forcing the surface to run hotter than the radiative baseline to shed the same energy from a higher, colder emission level.
How does albedo change the equilibrium temperature?
Albedo A is the fraction of incident starlight reflected without being absorbed, so only (1−A) contributes to heating. Because it enters the formula as (1−A)^¼, its effect is muted: raising albedo from 0 to 0.30 lowers T_eq by only about 8 percent. Venus reflects roughly 75 percent of sunlight (A ≈ 0.77 to 0.90 depending on definition), giving it a low equilibrium temperature near 230 K — yet its runaway greenhouse pushes the actual surface to 737 K, the hottest in the Solar System.
Does the planet's own size affect its equilibrium temperature?
No. The planet's radius cancels out. It intercepts starlight over its cross-sectional disk (πR_p²) and radiates over its full sphere (4πR_p²), so R_p appears on both sides of the balance and drops out. Equilibrium temperature depends only on the star (temperature and radius), the orbital distance, and the albedo — not on whether the planet is a small rock or a gas giant. Heat redistribution and rotation do matter for the true temperature, but not for this baseline.
What does 'heat redistribution' mean and why does it change the answer?
The standard formula assumes the absorbed energy is spread evenly over the whole sphere before being re-emitted — full redistribution, the case for a fast-rotating planet with a thick atmosphere. If instead only the dayside radiates (no redistribution, common for tidally locked hot Jupiters), the same energy leaves from half the area, raising the substellar temperature by a factor of 2^¼ ≈ 1.19, about 19 percent. Measured dayside temperatures of hot Jupiters therefore run hotter than their nominal equilibrium temperature.
How do astronomers use equilibrium temperature for exoplanets?
It's a fast, model-light way to sort thousands of planets. Because it needs only the star's temperature and radius and the orbital distance (all derivable from a transit and radial-velocity data), an albedo can be assumed and T_eq computed for essentially every confirmed planet. Values near 200 to 320 K flag potentially temperate worlds worth follow-up; values above ~1000 K mark hot Jupiters and lava worlds. It defines the classical habitable zone as the orbital band where T_eq is compatible with liquid water given a plausible atmosphere.
Is equilibrium temperature the same as effective temperature?
They use the same blackbody idea but describe different objects. A star's effective temperature is set by its own internal luminosity radiating from its surface. A planet's equilibrium temperature is set by external starlight it absorbs and re-emits — a planet has no significant internal furnace (Earth's internal heat flux is about 0.09 W/m², roughly 2500 times smaller than absorbed sunlight). Both are defined via the Stefan-Boltzmann law, L = 4πR²σT⁴, but one is powered from within and the other from without.