Kinetics
Activation Energy
Why thermodynamically favorable reactions can still be slow at room temperature
Activation energy (Ea) is the minimum energy a colliding pair of molecules must possess for a reaction to occur. It is the height of the barrier separating reactants from products on the potential-energy surface, and it sets how rapidly temperature accelerates a reaction through the Arrhenius equation k = A·exp(−Ea/RT).
- SymbolEa
- UnitskJ/mol
- Typical range0 – 400 kJ/mol
- Equationk = A·exp(−Ea/RT)
- Coined byArrhenius, 1889
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The barrier on the energy landscape
Imagine the molecules involved in a reaction as a ball rolling across a hilly landscape. The reactants sit in one valley, the products in another, and to get from one to the other the ball must roll up over a hill. The height of the hill, measured from the reactant valley floor, is the activation energy.
Energy
│
│ ╱─── Transition state ───╲
│ ╱ ↑ ╲
│ ╱ Ea ╲
│ ╱ ↓ ╲
│ ──┘ (forward) ╲
│ Reactants ╱──── Products
│ ╱ │
│ ↑ ╱ │
│ ΔH (rxn) ╱ │
│ ↓ ╱ │
│ ──┘ │
└──────────────────────────────────────────────→
Reaction coordinate
Ea is purely kinetic: it controls how fast the reaction goes. ΔH is purely thermodynamic: it controls whether the reaction is downhill overall. The two are completely independent. A reaction can be wildly exothermic (large negative ΔH) and still be unmeasurably slow at room temperature (large Ea). Diamond → graphite is the canonical example: ΔH = −2 kJ/mol, Ea ≈ 540 kJ/mol, half-life of a diamond at 25 °C ≈ 10⁸⁰ years.
The transition state at the top of the hill is not an isolable species. It is a fleeting molecular geometry — bonds partly broken, others partly formed — that exists for ~10⁻¹³ seconds before falling into either valley. Its energy relative to the reactants is exactly Ea.
The Boltzmann tail and the exponential
At thermal equilibrium, molecular kinetic energies follow a Maxwell–Boltzmann distribution. The fraction of collisions with energy ≥ Ea is approximately:
fraction ≈ exp(−Ea / RT)
That is the magic exponential. R = 8.314 J/(mol·K), T is absolute temperature in kelvin. Multiply that fraction by the total collision frequency A and you have the Arrhenius rate constant:
k = A · exp(−Ea / RT)
Take the natural log of both sides and you get the linearized form, which is what experimentalists actually plot:
ln(k) = ln(A) − Ea/(R·T)
A plot of ln(k) versus 1/T is a straight line with slope −Ea/R and intercept ln(A). Three measurements at three temperatures give you Ea to ~5 % accuracy.
Worked example: doubling time per 10 K
A widely-quoted rule of thumb says reaction rates double for every 10 K increase. The actual factor depends on Ea and on the absolute temperature. For Ea = 50 kJ/mol, going from 298 K to 308 K:
k₂/k₁ = exp[(Ea/R)·(1/T₁ − 1/T₂)]
= exp[(50,000/8.314)·(1/298 − 1/308)]
= exp[6,015 · (3.356×10⁻³ − 3.247×10⁻³)]
= exp[6,015 · 1.09×10⁻⁴]
= exp[0.656]
= 1.93×
About a doubling, as advertised. But for Ea = 100 kJ/mol the same 10 K jump gives k₂/k₁ ≈ 3.7×; for Ea = 25 kJ/mol it gives only 1.4×. The "double per 10 K" rule applies for moderate barriers near room temperature; the real answer is always exp[(Ea/R)·(1/T₁ − 1/T₂)].
How catalysts lower Ea
A catalyst opens a new path on the energy surface — typically by binding the reactants in an arrangement that resembles the transition state, lowering the barrier the reactants have to climb. The reactants and products sit in the same valleys; the hill in between is replaced by a saddle pass at lower altitude.
Energy
│ ╱──── uncatalyzed TS (Ea = 75) ──╲
│ ╱ ╲
│ ╱ ╱── catalyzed TS (Ea = 40) ──╲ ╲
│ ──┘ ╱ ╲╲╲╲╲╲
│ R ╱ ╲──── P
│ ──┘ ──
└─────────────────────────────────────────────────────→
Numerically: dropping Ea from 75 to 40 kJ/mol at 298 K accelerates the reaction by a factor of exp[(75 − 40)·1000/(8.314·298)] = exp[14.1] ≈ 1.3 × 10⁶. A 35 kJ/mol barrier reduction = a million-fold rate increase. That is why enzymes — which routinely cut Ea by 50–100 kJ/mol — accelerate biochemistry by 10⁸ to 10¹⁷ over the uncatalyzed reaction.
Crucially, the catalyst is not consumed and the equilibrium constant K = exp(−ΔG/RT) is unchanged. The forward and reverse rates both increase by the same factor, leaving K = k_forward / k_reverse where it was.
Activation energy vs bond dissociation energy
| Activation energy (Ea) | Bond dissociation energy (BDE) | |
|---|---|---|
| What it measures | Barrier to a reaction | Energy to break one bond into radicals |
| Reaction-specific | Yes — different per pathway | Yes — but pathway-agnostic |
| Always positive | Yes (barrier-less = 0) | Yes |
| Reduced by catalysts | Yes | No (it's a property of the bond) |
| Typical range | 0 – 400 kJ/mol | 150 – 1100 kJ/mol |
| Determines | Reaction speed at given T | Whether radical chain can propagate |
| Measured by | Arrhenius plot of rate vs T | Photolysis, pyrolysis, MS |
For unimolecular bond fission with no rearrangement, Ea ≈ BDE. For everything else — concerted mechanisms, bimolecular substitutions, rearrangements — Ea is smaller, sometimes much smaller, because new bonds form as old ones break.
Where activation energy controls outcomes
- Refrigeration of food. Most spoilage reactions (Maillard, lipid oxidation, microbial growth) have Ea in the 50–80 kJ/mol range. Lowering temperature from 25 °C to 4 °C slows them by ~5×; from 25 °C to −18 °C by ~50×. That is why a freezer extends shelf life from weeks to months.
- Engine knock and octane rating. Auto-ignition of gasoline depends on the slowest C–H abstraction step. Branched alkanes (iso-octane) have higher Ea than straight chains (n-heptane), so they auto-ignite later in the compression stroke. Octane rating is a kinetic quantity dressed up as a percentage.
- Atmospheric chemistry. The OH + CH₄ reaction (which sets methane's atmospheric lifetime) has Ea ≈ 14 kJ/mol — small enough that the reaction proceeds at 273 K, large enough that tropospheric methane survives 12 years before oxidation.
Measuring Ea: the two-point shortcut
The quickest experimental determination uses two temperatures rather than a full plot:
ln(k₂/k₁) = (Ea/R) · (1/T₁ − 1/T₂)
Ea = R · ln(k₂/k₁) / (1/T₁ − 1/T₂)
Worked example. A reaction has rate constant 1.2 × 10⁻³ s⁻¹ at 300 K and 4.8 × 10⁻³ s⁻¹ at 320 K.
ln(4.8/1.2) = ln(4) = 1.386
1/300 − 1/320 = 3.333×10⁻³ − 3.125×10⁻³ = 2.083×10⁻⁴
Ea = 8.314 · 1.386 / 2.083×10⁻⁴
= 8.314 · 6,651
= 55,300 J/mol
≈ 55 kJ/mol
Three temperatures and a least-squares fit give better accuracy and confidence intervals, but two are enough for an order-of-magnitude estimate.
Common pitfalls
- Confusing Ea with ΔH. Ea is the barrier height from reactants up to the transition state; ΔH is the level difference between reactants and products. They are perpendicular axes of the energy diagram, not the same number.
- Reporting "the activation energy of compound X." Ea is a property of a reaction, not a substance. The same compound has different Ea for hydrolysis, oxidation, and isomerization.
- Using the wrong T. The Arrhenius equation requires absolute temperature in kelvin. Plugging in 25 (instead of 298) is the most-debugged error in undergraduate kinetics labs.
- Assuming Arrhenius is exact. Real Ea has a weak temperature dependence (modified Arrhenius adds a Tⁿ pre-factor). Treating Ea as constant is fine over 50–100 K windows but degrades over wider ranges.
- Confusing observed Ea with elementary-step Ea. If the rate law combines several steps, the experimentally fitted "Ea_obs" is an effective barrier — a weighted combination of step energies, not a single bond energy.
- Forgetting that catalysts work in both directions. A catalyst that accelerates A → B by 10⁶ also accelerates B → A by 10⁶. Selective catalysis exploits the fact that competing reactions don't share the same lowered path.
Variants and refinements
- Modified Arrhenius equation. k = A · Tⁿ · exp(−Ea/RT). The Tⁿ factor captures the slow temperature dependence of A predicted by collision theory and transition-state theory.
- Eyring equation. The transition-state-theory analogue: k = (k_B·T/h)·exp(−ΔG‡/RT). Replaces Ea with a free energy of activation that splits into ΔH‡ and ΔS‡, separating barrier height from entropic constraints.
- Marcus theory. For electron-transfer reactions, Ea is given by (λ + ΔG)²/(4λ) where λ is reorganization energy. Predicts the famous "inverted region" where increasing driving force slows the reaction.
- Tunneling corrections. Light atoms (H, D) can tunnel through the barrier rather than going over. Ea derived from Arrhenius plots of H- vs D-containing reactions reveals tunneling when kH/kD >> 7.
Frequently asked questions
Why does temperature have such a dramatic effect on reaction rate?
Because the fraction of molecules with energy ≥ Ea follows a Boltzmann tail: exp(−Ea/RT). The exponential makes the rate depend supersensitively on T. For Ea = 50 kJ/mol, raising T from 298 K to 308 K (just 10 K) doubles the rate. For Ea = 100 kJ/mol, the same 10 K bump quadruples it. The pre-factor A barely changes; the exp term does almost all the work.
How is Ea different from ΔH of reaction?
Ea is the height of the barrier from reactants to the transition state — a kinetic quantity. ΔH is the energy difference from reactants to products — a thermodynamic quantity. A reaction can be very exothermic (large negative ΔH) yet have a high Ea, in which case it is thermodynamically favorable but kinetically slow. Diamond → graphite is the textbook example: ΔH = −2 kJ/mol but Ea is over 540 kJ/mol, so diamonds last.
How is Ea measured?
Run the reaction at three or more temperatures, fit ln(k) vs 1/T to a straight line. The slope is −Ea/R. Two-point version: Ea = R·ln(k₂/k₁) / (1/T₁ − 1/T₂). Modern instruments do this automatically; a temperature-controlled UV-vis or stopped-flow spectrometer can determine Ea in an afternoon.
Do catalysts change ΔH?
No — they only change Ea. The reactants and products are the same compounds at the same conditions, so the enthalpy difference between them is unchanged. Catalysts open a new path with a lower barrier; the energy of the reactant well and the product well stay where they were. This is why a catalyst can never change the equilibrium constant, only how fast it is reached.
Can activation energy be zero?
Yes, for radical-radical recombinations and some ion-ion gas-phase reactions, Ea can be effectively 0 — every collision succeeds. The rate is then limited only by the collision frequency. Liquid-phase examples include the recombination of solvated electrons. These are the upper-speed-limit reactions in chemistry, with rate constants near 10¹⁰ M⁻¹s⁻¹.
What is the relationship between Ea and bond dissociation energy?
For a reaction whose rate-limiting step breaks a single bond cleanly (e.g. unimolecular decomposition of a peroxide), Ea ≈ BDE of that bond. For most bimolecular reactions, Ea is smaller than the BDE of any one bond because the new bond starts forming as the old one breaks — partial overlap saves energy. The Hammond postulate predicts when the transition state resembles reactants (Ea small) versus products (Ea large).