Solutions
Common-Ion Effect
Adding a shared ion to shut down dissolving
The common-ion effect is the drop in solubility (or in ionization) of a substance when you add a second soluble compound that supplies an ion the substance already has in solution. The shared "common ion" raises that ion's concentration, the ion product climbs above the solubility product Ksp, and Le Chatelier's principle drives the equilibrium backward — precipitating more solid or suppressing the acid's dissociation. For silver chloride, switching from pure water to 0.10 M NaCl cuts solubility about 7000-fold, from 1.3×10⁻⁵ M down to ~1.8×10⁻⁹ M.
- Core ideaAdd a shared ion → solubility falls
- DriverLe Chatelier equilibrium shift
- AgCl in waters ≈ 1.3×10⁻⁵ M
- AgCl in 0.10 M NaCls ≈ 1.8×10⁻⁹ M (~7000× less)
- Ksp(AgCl, 25 °C)1.8×10⁻¹⁰
- Constants unchangedKsp, Ka fixed — only position moves
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What the common-ion effect is
Drop a pinch of table salt into a beaker that is already a saturated solution of silver chloride and something quietly dramatic happens: the liquid goes faintly cloudy as fresh white solid drifts out of solution. Nothing was added that contains silver, yet more silver chloride precipitates. That counterintuitive result is the common-ion effect — the suppression of a substance's solubility (or of a weak electrolyte's ionization) when a second, fully soluble compound supplies an ion that the first substance already contributes to the solution.
The key word is common: the added salt and the dissolving salt share an ion. Sodium chloride and silver chloride both put chloride into the water. Once you flood the solution with chloride from the freely soluble NaCl, the sparingly soluble AgCl can no longer hold as much silver and chloride in solution simultaneously, so the excess crashes out. The effect is not a new law of nature — it is Le Chatelier's principle applied to an ionic equilibrium, named for the special case where the stress you apply is an ion the system already owns.
The mechanism: Q, Ksp, and the equilibrium shift
A slightly soluble ionic solid sits in dynamic equilibrium with its dissolved ions:
AgCl(s) ⇌ Ag⁺(aq) + Cl⁻(aq)
The position of that equilibrium is fixed by the solubility product constant, Ksp = [Ag⁺][Cl⁻] = 1.8×10⁻¹⁰ at 25 °C. In pure water the solid dissolves until both ion concentrations equal the molar solubility s, so s² = Ksp and s = √(1.8×10⁻¹⁰) ≈ 1.34×10⁻⁵ M. Roughly 13 micromoles of silver per liter — already not much.
Now add 0.10 M NaCl. Sodium chloride is fully soluble, so it dumps 0.10 M chloride into the beaker instantly. The reaction quotient Q = [Ag⁺][Cl⁻] momentarily becomes (1.34×10⁻⁵)(0.10) ≈ 1.3×10⁻⁶, which is about 7000 times larger than Ksp. The solution is now supersaturated: Q > Ksp. Le Chatelier's principle says a system stressed by extra product will shift to consume it, so silver and chloride combine and deposit as solid until Q falls back to 1.8×10⁻¹⁰. Solving for the new solubility:
s(0.10 + s) = 1.8×10⁻¹⁰ → s ≈ 1.8×10⁻¹⁰ / 0.10 = 1.8×10⁻⁹ M
(The approximation 0.10 + s ≈ 0.10 is excellent because s is nanomolar.) Solubility has collapsed from ~13 µM to under 2 nM — a 7000-fold reduction — purely by adding an ion that contains no silver at all. Crucially, Ksp itself never changed. Equilibrium constants depend only on temperature; what moved was the equilibrium position, redistributing matter between solid and solution to keep the product of ion concentrations pinned at 1.8×10⁻¹⁰.
Working the numbers across salts
The size of the effect scales with Ksp and with how many ions the formula produces. A 1:1 salt like AgCl loses solubility in direct proportion to the common-ion concentration. A 1:2 salt like lead(II) iodide, PbI₂ ⇌ Pb²⁺ + 2 I⁻ with Ksp = 7.1×10⁻⁹, is even more sensitive to a common iodide because iodide appears squared in the expression: s = Ksp/[I⁻]². The table below makes the leverage concrete.
| System | Ksp (25 °C) | Solubility in pure water | Solubility with common ion | Fold decrease |
|---|---|---|---|---|
| AgCl in 0.10 M NaCl | 1.8×10⁻¹⁰ | 1.3×10⁻⁵ M | 1.8×10⁻⁹ M | ~7,400× |
| BaSO₄ in 0.10 M Na₂SO₄ | 1.1×10⁻¹⁰ | 1.0×10⁻⁵ M | 1.1×10⁻⁹ M | ~9,500× |
| PbI₂ in 0.10 M KI | 7.1×10⁻⁹ | 1.2×10⁻³ M | 7.1×10⁻⁷ M | ~1,700× |
| CaF₂ in 0.10 M NaF | 3.9×10⁻¹¹ | 2.1×10⁻⁴ M | 3.9×10⁻⁹ M | ~54,000× |
| Mg(OH)₂ in 0.10 M NaOH | 5.6×10⁻¹² | 1.1×10⁻⁴ M | 5.6×10⁻¹⁰ M | ~200,000× |
Notice the pattern: salts whose anion (or cation) is squared in the Ksp expression — fluoride in CaF₂, hydroxide in Mg(OH)₂ — show the most violent collapse, because driving up a squared term in the denominator crushes solubility quadratically. This is why a modest 0.10 M excess of hydroxide can lower Mg(OH)₂ solubility by five orders of magnitude.
The same effect in weak acids and bases
The common-ion effect is not limited to dissolving solids. A weak acid ionizes only partly, and that ionization is an equilibrium too:
CH₃COOH ⇌ H⁺ + CH₃COO⁻, Ka = 1.8×10⁻⁵ (pKa = 4.74)
Pure 0.10 M acetic acid gives [H⁺] = √(Ka × C) ≈ √(1.8×10⁻⁶) ≈ 1.3×10⁻³ M, a pH of about 2.87, with roughly 1.3 % of the acid ionized. Now add 0.10 M sodium acetate. Acetate is the common ion shared with the acid's ionization, so it stresses the equilibrium from the product side. Dissociation is suppressed, ionization falls toward ~0.018 %, and the pH climbs. Plugging into Ka:
[H⁺] = Ka × ([acid]/[base]) = 1.8×10⁻⁵ × (0.10/0.10) = 1.8×10⁻⁵ M → pH = 4.74
That jump from pH 2.87 to 4.74, with the acid's dissociation throttled by its own conjugate base, is exactly the chemistry of a buffer. The common ion is what makes a buffer resist change: there is a large reservoir of un-ionized acid held back by the added acetate, ready to neutralize any base, and a large reservoir of acetate ready to mop up acid. Ammonia behaves symmetrically — adding ammonium chloride supplies the common NH₄⁺ ion and suppresses the ionization of NH₃, lowering [OH⁻] and giving a basic buffer.
When the effect bends or breaks
Push a common ion to high concentration and two competing phenomena spoil the simple picture. First, complex-ion formation: silver chloride that has precipitated in modest chloride will re-dissolve in a large excess of chloride because Ag⁺ binds extra Cl⁻ to form soluble AgCl₂⁻ and AgCl₃²⁻ complexes. Plot AgCl solubility against [Cl⁻] and you see a minimum near 10⁻³–10⁻² M chloride, then a rise — the common-ion effect wins at first and loses later. Second, the salt effect (or "uncommon-ion effect"): adding any inert electrolyte, even one with no shared ion, raises ionic strength, lowers the activity coefficients of the dissolved ions, and lets more salt dissolve to satisfy the activity-based Ksp. Rigorous work therefore writes Ksp in terms of activities, a = γ·[concentration], and uses Debye–Hückel theory to estimate γ. For the introductory case these corrections are small, but they explain why measured solubilities never fall quite as far as the naive calculation predicts, and why very concentrated solutions can reverse the trend.
Where it matters
- Gravimetric analysis. To weigh an analyte accurately, you precipitate it as completely as possible. Adding a slight excess of the precipitating reagent — a common ion — drives residual analyte out of solution, often leaving under 0.1 % behind, well within analytical tolerance.
- Qualitative cation separation. Classic schemes drop metal sulfides and hydroxides in groups by controlling a common ion (S²⁻ via H₂S at tuned pH, or OH⁻), so cations precipitate selectively rather than all at once.
- Buffers in blood and the lab. The bicarbonate buffer keeping blood at pH 7.4 and benchtop acetate or phosphate buffers all rely on a conjugate common ion suppressing ionization.
- Salting-out. Soap is separated from glycerol by adding NaCl: the common Na⁺ (and the ionic-strength change) forces the sodium carboxylate out of solution. Dyes and proteins are precipitated the same way.
- Industrial precipitation. The Solvay process and many metallurgical recoveries push product ions to crystallize useful solids; controlled common-ion addition maximizes yield.
- Biology and medicine. Kidney-stone formation (calcium oxalate, calcium phosphate) and tooth-enamel dissolution are common-ion problems — raising or lowering shared Ca²⁺, phosphate, or fluoride shifts whether the mineral dissolves or deposits. Fluoride toothpaste exploits the effect to stabilize enamel.
Common ion vs. uncommon ion at a glance
| Aspect | Common-ion effect | Salt (uncommon-ion) effect |
|---|---|---|
| Added species | Shares an ion with the salt | Inert electrolyte, no shared ion |
| Direction on solubility | Decreases it | Slightly increases it |
| Mechanism | Le Chatelier shift, Q > Ksp | Lower activity coefficients (γ) |
| Magnitude | Large (orders of magnitude) | Small (tens of percent) |
| Constant affected | None — position moves | None — activities adjust |
Frequently asked questions
What is the common-ion effect?
The common-ion effect is the decrease in solubility of a sparingly soluble salt (or the suppression of a weak electrolyte's ionization) when you add a second, fully soluble compound that shares one of its ions. The added ion is the "common ion." By Le Chatelier's principle, raising the concentration of a product ion pushes the dissolution equilibrium backward, so more solid precipitates and less salt stays dissolved. It is a special, ion-specific case of a general equilibrium shift.
How does the common-ion effect lower solubility?
Solubility is governed by Ksp = [cation][anion]. Add a common ion and that ion's concentration jumps, so the ion product Q = [cation][anion] temporarily exceeds Ksp. The supersaturated system relieves the stress by combining ions back into solid until Q falls to Ksp again. For AgCl in 0.10 M NaCl, solubility s satisfies s × (s + 0.10) ≈ s × 0.10 = 1.8×10⁻¹⁰, giving s ≈ 1.8×10⁻⁹ M — roughly 7000 times lower than the 1.3×10⁻⁵ M seen in pure water.
Is the common-ion effect just Le Chatelier's principle?
Yes — it is Le Chatelier's principle applied to an ionic equilibrium. Adding a species that is already on the product side stresses the equilibrium, and the system responds by shifting toward reactants (the solid, or the un-ionized weak acid). The "common-ion" label simply names the case where the added species is an ion shared with the dissolving salt or ionizing acid. Ksp and Ka stay constant; only the equilibrium position moves.
How does the common-ion effect explain buffers?
A buffer of acetic acid (CH₃COOH, Ka = 1.8×10⁻⁵) plus sodium acetate is a common-ion system. The acetate ion from the salt is common to the acid's ionization equilibrium, so it suppresses dissociation of CH₃COOH and holds [H⁺] near the pKa. In 0.10 M acetic acid alone, pH ≈ 2.87; add 0.10 M acetate and the common ion drives pH up to 4.74. This suppressed ionization is exactly why buffers resist pH change.
When does the common-ion effect fail or reverse?
At low added-salt concentrations the effect dominates and solubility drops. But adding a large excess of certain ions can reverse it: complex-ion formation (e.g., AgCl + excess Cl⁻ → AgCl₂⁻) re-dissolves the solid, and high ionic strength raises solubility via the "salt effect" (uncommon-ion effect), because activity coefficients fall and the activity-based Ksp is satisfied at higher analytical concentrations. So very concentrated common-ion solutions can show a solubility minimum followed by an upturn.
Where is the common-ion effect used in practice?
Gravimetric analysis adds an excess of precipitating reagent so almost all analyte drops out as solid for accurate weighing. Qualitative analysis separates metal sulfides and hydroxides by tuning a common ion (sulfide or hydroxide) to precipitate cations one group at a time. Industrially, salting-out crystallizes soap and dyes; the Solvay process exploits common Na⁺/HCO₃⁻ ions; and kidney-stone and tooth-enamel chemistry both hinge on common-ion control of Ca²⁺ and phosphate solubility.