Physical Chemistry
Dalton's Law of Partial Pressures
Each gas in a mixture pushes as if alone — the pressures add
Dalton's law states that the total pressure of a non-reacting gas mixture equals the sum of partial pressures of its components: P_total = ΣP_i. Each gas behaves as if it alone occupied the volume. Earth's atmosphere at 1 atm decomposes into 0.78 atm N₂, 0.21 atm O₂, 0.01 atm Ar, and trace gases.
- Core equationP_total = P₁ + P₂ + ... + P_n
- Mole-fraction formP_i = X_i · P_total
- DiscoveredJohn Dalton, 1801
- Air at sea level0.78 N₂ + 0.21 O₂ + 0.01 Ar atm
- ValidityIdeal, non-reacting mixtures
- Fails atHigh P, low T, reactive mixes
Interactive visualization
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How partial pressures work
Imagine a sealed flask containing only nitrogen at 0.78 atm. Now inject oxygen until it alone would reach 0.21 atm in that same flask, plus a sliver of argon at 0.01 atm. The pressure gauge now reads 1.00 atm — exactly the sum. The gases have not interacted; each species pushes the walls as if the others were absent. That is Dalton's law in one sentence.
The reason is mechanical. Gas pressure comes from billions of molecular collisions per second against the container walls. In an ideal gas each molecule travels independently — point-like, no forces between them. A nitrogen molecule colliding with the wall does not care whether oxygen molecules share the volume. Every species contributes its own collision rate, set only by its own concentration and the temperature.
From the ideal gas law applied to each component:
P_i = n_i · R · T / V (each species, same V and T)
P_total = (n_1 + n_2 + ... + n_n) · R · T / V
= P_1 + P_2 + ... + P_n
Dividing one by the other gives the mole-fraction form: P_i / P_total = n_i / n_total = X_i, so P_i = X_i · P_total. For ideal gases, mole fraction, volume fraction, and pressure fraction are interchangeable.
Worked example — three-component mixture
A 5.00 L tank at 298 K is loaded with 0.30 mol N₂, 0.20 mol O₂, and 0.10 mol CO₂. Find the total pressure and each partial pressure.
n_total = 0.30 + 0.20 + 0.10 = 0.60 mol
P_total = nRT / V
= (0.60 mol)(0.0821 L·atm·mol⁻¹·K⁻¹)(298 K) / (5.00 L)
= 14.68 / 5.00
= 2.94 atm
X(N₂) = 0.30 / 0.60 = 0.500 → P(N₂) = 0.500 · 2.94 = 1.47 atm
X(O₂) = 0.20 / 0.60 = 0.333 → P(O₂) = 0.333 · 2.94 = 0.98 atm
X(CO₂) = 0.10 / 0.60 = 0.167 → P(CO₂) = 0.167 · 2.94 = 0.49 atm
Check: 1.47 + 0.98 + 0.49 = 2.94 atm ✓
Notice that the result is independent of which gases are present. Replacing CO₂ with helium would give the same total pressure and the same numerical breakdown — the mole fraction, not the chemical identity, sets the partial pressure.
Real-world specs
| Mixture | Conditions | Partial pressure of interest |
|---|---|---|
| Sea-level air | 1.00 atm, 25 °C | pO₂ = 0.21 atm = 160 mmHg |
| Mt. Everest summit | 0.33 atm, −36 °C | pO₂ = 0.069 atm = 53 mmHg |
| Arterial blood | Body, 37 °C | pO₂ = 100 mmHg, pCO₂ = 40 mmHg |
| Scuba air at 30 m | 4.0 atm | pO₂ = 0.84 atm, pN₂ = 3.12 atm |
| Heliox (50/50) at 60 m | 7.0 atm | pO₂ = 3.5 atm, pHe = 3.5 atm |
| Anaesthesia mix (sevoflurane) | 1 atm | p(sevoflurane) = 0.02 atm |
| Hydrogen collected over water | 22 °C, 750 mmHg | pH₂ = 750 − 19.83 = 730.17 mmHg |
The atmospheric column itself is the world's biggest demonstration. Climbers above 8,000 m enter the "death zone" not because the air composition changes — it doesn't, the 21% O₂ ratio holds — but because total pressure drops, dragging pO₂ below the threshold tissues need.
Dalton's law vs other gas relations
| Dalton's law | Amagat's law | Raoult's law | Henry's law | |
|---|---|---|---|---|
| What's additive | Pressures at fixed V, T | Volumes at fixed P, T | Vapor P over solution | Dissolved gas in liquid |
| Equation | P_total = ΣP_i | V_total = ΣV_i | P_i = X_i · P_i* | p_i = k_H · c_i |
| Phase | Gas mixture | Gas mixture | Liquid–vapor | Gas–liquid |
| Component independence | Yes (no IMFs) | Yes (additive volumes) | Ideal solution | Dilute solute |
| Year | 1801 | 1880 | 1887 | 1803 |
| Failure mode | Reactive / dense gas | High P deviations | Non-ideal mixing | High concentration |
Amagat's law is the volumetric twin of Dalton's: at fixed total pressure each gas would occupy a "partial volume" V_i, and these add to V_total. For ideal gases the two laws contain the same information. Raoult and Henry are not gas-mixture statements at all — they describe equilibrium between a gas and a liquid solution — but they share the Dalton-style mole-fraction structure.
ASCII visualization
BEFORE MIXING AFTER MIXING (same V, T)
N₂ alone O₂ alone Ar alone N₂ + O₂ + Ar
┌────────┐ ┌────────┐ ┌────────┐ ┌──────────────┐
│ N N N │ │ O │ │ A │ │ N O A N N │
│ N N N │ + │ O O │ + │ A │ = │ O N A O │
│ N N │ │ O O │ │ │ │ N A N O N │
└────────┘ └────────┘ └────────┘ └──────────────┘
P = 0.78 P = 0.21 P = 0.01 P_total = 1.00
Each species' contribution to wall collisions is unchanged.
Total pressure = sum of independent partial pressures.
Variants and corrections
- Real-gas correction. When intermolecular forces matter (CO₂ above 50 atm, water vapor near saturation), each component's effective pressure is its fugacity f_i, not its raw P_i. The Lewis-Randall rule generalises Dalton: f_i(mixture) = X_i · f_i(pure). For modest deviations a virial expansion adds cross terms B_ij that couple species pairs.
- Chemical equilibrium. If the gases react (e.g. N₂ + 3H₂ ⇌ 2NH₃), Dalton's law still applies to whatever mixture exists at any instant — but the moles change as the reaction proceeds, so partial pressures shift along the way. The equilibrium constant Kp is written in those final partial pressures.
- Wet-gas measurements. Gas collected over water carries water vapor at the saturation pressure for that temperature. The measured pressure is P_total = P_dry + P(H₂O), and you subtract a tabulated P(H₂O) to recover the dry-gas value.
- Daltonian fraction in flowing systems. In gas chromatography and mass spectrometry, mole fractions in a flowing carrier are computed from peak areas; partial pressures inside the detector chamber are X_i · P_chamber. The same formula does double duty.
Common pitfalls and failure modes
- Forgetting water vapor. Lab samples collected over water are wet by definition. Reporting P_total as the dry-gas pressure overestimates the moles of analyte by a few percent at room temperature, more at higher temperatures.
- Applying it to reactive mixtures. Mix NH₃ and HCl at room temperature and the pressure drops as solid NH₄Cl forms. The "law" still holds at every instant, but the mole counts are now functions of time.
- Treating it as exact at high pressure. Above roughly 10 atm for small molecules, intermolecular forces between unlike species shift the partial pressures by a few percent. Industrial reactor design uses fugacity coefficients, not raw mole fractions.
- Ignoring temperature units. If you compute P_total from PV = nRT for the mixture and then check against the sum, every component must be evaluated at the same Kelvin temperature. Mixing 25 °C and 298 K gives nonsense.
- Confusing partial pressure with concentration. P_i is a pressure (atm, Pa, mmHg), not a concentration. Henry's-law solubilities use the partial pressure of the gas above the liquid — not the total pressure of the mixture.
- Assuming "air" is constant. The 21% O₂ figure is dry-air composition. Humid tropical air at 35 °C contains up to 6% water vapor, so its O₂ mole fraction drops to ~19.7%. Aviators and athletes in humid heat feel this directly.
Frequently asked questions
What is Dalton's law of partial pressures?
Each gas in a non-reacting mixture exerts pressure as if alone in the container; the total is the sum. P_total = P_A + P_B + P_C + ... Each component's partial pressure equals its mole fraction times the total: P_i = X_i · P_total. Discovered by John Dalton in 1801 from observations of humid air.
Why do gases ignore each other?
In an ideal gas, particles are point-like and feel no intermolecular forces. So molecule A doesn't 'know' molecule B exists — it bounces off the walls at a rate set only by its own concentration and temperature. Each species contributes independently. This breaks down when gases react chemically (NH₃ + HCl → NH₄Cl) or when intermolecular forces matter (CO₂ near its critical point).
How do you compute partial pressure from mole fraction?
Mole fraction X_i = n_i / n_total. Then P_i = X_i · P_total. Example: a tank at 10 atm contains 0.6 mol N₂ and 0.4 mol O₂. X(N₂) = 0.6, X(O₂) = 0.4. P(N₂) = 6 atm, P(O₂) = 4 atm. The mole fraction equals the volume fraction equals the pressure fraction for ideal gases.
Why does Dalton's law matter for scuba diving?
At 30 m depth, ambient pressure is 4 atm. Breathing normal air (21% O₂), the partial pressure of oxygen is 0.84 atm — over four times the surface value. Above ~1.6 atm pO₂ becomes toxic (CNS oxygen toxicity). Trimix divers replace some N₂ with helium and reduce O₂ fraction so each partial pressure stays in safe ranges at depth.
How do you collect gas over water?
When a gas is collected by water displacement, the trapped sample is the gas plus water vapor. Apply Dalton's law: P_gas = P_total − P_water. At 25 °C the saturated water-vapor pressure is 23.76 mmHg. So if a sample reads 760 mmHg, the dry gas pressure is 760 − 23.76 = 736.24 mmHg. Forgetting this correction is a classic lab-report error.
When does Dalton's law fail?
When gases react (the moles change), when intermolecular forces are large (high pressure, low temperature), and when one component is near its dew point (water vapor in cold humid air condenses, dropping its partial pressure). For real-gas mixtures the Lewis-Randall rule and fugacities replace simple additivity.