Analytical Chemistry

Infrared Spectroscopy

Reading molecules by their vibrational fingerprints

Infrared (IR) spectroscopy bounces or transmits IR light through a sample and records which wavelengths the molecule absorbs. Each absorption corresponds to a vibrational mode — a stretch or bend of one of the bonds — and each functional group has a characteristic frequency range. C=O lands near 1700 cm⁻¹, O–H near 3300, C≡N near 2200. With a modern Fourier-transform IR (FTIR) spectrometer and an attenuated-total-reflectance (ATR) accessory, you can identify a neat compound in under a minute, no sample prep.

  • RegionMid-IR, 4000 – 400 cm⁻¹
  • Selection ruleΔ dipole ≠ 0
  • Resolution1 – 4 cm⁻¹ (FTIR)
  • Sample prepATR: none. KBr disc, neat film, gas cell
  • DiagnosticFunctional groups (4000 – 1500 cm⁻¹)
  • Fingerprint region1500 – 400 cm⁻¹
  • Acquisition time~ 1 min, 16 scans

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How IR works

Molecules vibrate. The atoms in a chemical bond aren't rigidly bolted together — they oscillate around an equilibrium distance like masses on a spring. Quantum mechanics quantises these oscillations into discrete energy levels, and the gaps between levels happen to coincide with the energy of infrared photons. Shine an IR beam at a sample and a photon whose energy matches a vibrational gap gets absorbed; everything else passes through. Plot transmittance or absorbance against wavenumber and you have an IR spectrum.

The frequency of the absorbed photon depends on two things: the stiffness of the bond (force constant k) and the masses of the atoms it joins (reduced mass µ). Hooke's-law oscillator model:

ν̃ = (1 / 2πc) √(k / µ)
µ = (m₁ × m₂) / (m₁ + m₂)

The math predicts the gross trends. Triple bonds are stiffer than double bonds are stiffer than single bonds, so C≡C (~2200 cm⁻¹) > C=C (~1650 cm⁻¹) > C–C (~1100 cm⁻¹). Light atoms vibrate faster than heavy ones, so C–H (~3000 cm⁻¹) > C–D (~2200 cm⁻¹) > C–C. Memorise those two scaling laws and you've got an intuition for half the IR table.

Not every vibration absorbs. The IR selection rule is: a vibration must change the molecular dipole moment to be IR-active. The symmetric stretch of N₂ doesn't change the dipole (zero throughout), so N₂ has zero IR absorption — atmospheric nitrogen is invisible to IR, which is why IR can probe the rest of the air. Asymmetric stretches and polar bonds are bright; symmetric stretches in homonuclear diatomics are dark.

The diagnostic-band cheat sheet

The working chemist's brain runs on this table:

Functional groupWavenumber (cm⁻¹)IntensityNotes
O–H, alcohol3200 – 3550Strong, broadHydrogen bonded; sharp at 3650 if free.
O–H, carboxylic acid2500 – 3300Very broadDistinctive boulder-shaped band.
N–H, primary amine3300 – 3500Medium, two bandsSymmetric and asymmetric stretches.
N–H, secondary amine3300 – 3400Medium, single bandOnly one N–H to stretch.
C–H, sp³ alkyl2850 – 2960MediumBelow 3000.
C–H, sp² vinyl/aromatic3000 – 3100MediumAbove 3000 — classic split.
C–H, aldehyde2700 – 2850Medium, two bandsDiagnostic doublet plus C=O.
C≡C, alkyne2100 – 2260Weak (terminal stronger)Often weak; symmetric internal alkynes invisible.
C≡N, nitrile2200 – 2260Medium, sharpDistinctive narrow peak in dead window.
C=O, carbonyl1670 – 1820Very strongThe most diagnostic band in IR.
C=C, alkene1620 – 1680VariableStronger if polar (cis vs trans).
C=C, aromatic1450 – 1600VariableMultiple bands; ring breathing.
C–O, ether/ester1000 – 1300StrongBroad; sits in fingerprint region.
N–O, nitro1300 – 1550Strong, two bandsAsymmetric and symmetric NO₂ stretches.

The carbonyl zoo: one band, six diagnoses

The C=O stretch is the most useful diagnostic in IR because its position pins down the carbonyl class to ~20 cm⁻¹.

  • Acid anhydride: two bands, ~1820 and ~1750 cm⁻¹. Two coupled C=O stretches.
  • Acid chloride: ~1800 cm⁻¹. Cl is electron-withdrawing, raises C=O bond order.
  • Ester: ~1735 cm⁻¹ saturated, lower for conjugated. Plus strong C–O at 1170–1280 cm⁻¹.
  • Aldehyde: ~1725 cm⁻¹ (1700 if conjugated). Confirm with the C–H doublet at 2720/2820.
  • Ketone: ~1715 cm⁻¹ saturated, ~1680 if α,β-unsaturated, ~1660 if aryl.
  • Carboxylic acid: ~1710 cm⁻¹ plus that boulder-shaped O–H above 2500.
  • Amide: ~1680 cm⁻¹ (amide I band) plus N–H bending (amide II) at ~1550. Lowest C=O of the lot.

IR vs Raman vs ATR vs near-IR

TechniqueWhat gets absorbed/scatteredSelection ruleSample typeStrength
Mid-IR (transmission)4000–400 cm⁻¹ photonsΔ dipole ≠ 0Thin films, KBr discs, gas cellsQuantitative; long history
FTIR-ATR4000–400 cm⁻¹ via evanescent waveSame as mid-IRNeat liquids, powders, polymersNo sample prep; 30-second turnaround
RamanVisible-laser inelastic scatterΔ polarisability ≠ 0Aqueous solutions, gemstones, artWater-friendly; non-destructive; symmetric stretches
SERS (surface-enhanced)Raman on roughened metal surfaceSame as RamanTrace analytes adsorbed on Au/Ag10⁶–10¹⁰× enhancement; ppt detection
Near-IR (NIR)4000–14000 cm⁻¹ overtonesSame as mid-IR but weakerPharma tablets, grain, milk powderPenetrates packaging; non-contact PAT
Far-IR (terahertz)400–10 cm⁻¹SameCrystalline solids, pharmaceutical polymorphsLattice vibrations; metal-ligand bonds

IR and Raman are complementary because their selection rules differ. Symmetric vibrations (e.g., C=C in trans-stilbene) that are weak in IR are bright in Raman and vice versa. A polar bond's stretch is strong in IR (large dipole change) but often weak in Raman (small polarisability change). For unknown identification, having both spectra eliminates almost all ambiguity.

Worked example: an unknown C₈H₈O₂

You collect the FTIR of a colourless oil and observe:

  • Broad band centred at 2500–3300 cm⁻¹ (boulder shape).
  • Sharp doublet at 3050 and 2940 cm⁻¹.
  • Strong band at 1685 cm⁻¹.
  • Multiple bands 1450–1600 cm⁻¹.
  • Strong band at 1280 cm⁻¹.
  • Two bands at 750 and 705 cm⁻¹.

Reasoning. The 2500–3300 boulder = carboxylic acid O–H. The 1685 cm⁻¹ C=O is shifted lower than typical 1710 — conjugation with an aromatic ring. The aromatic C–H at 3050 and ring stretches at 1450–1600 confirm the aromatic. The two low-frequency C–H out-of-plane bends at 750 and 705 are the diagnostic mono-substituted-benzene fingerprint. C₈H₈O₂ with COOH and an aryl group → benzoic acid? But benzoic acid has the formula C₇H₆O₂, not C₈H₈O₂. The extra CH₂ between ring and COOH gives phenylacetic acid, C₆H₅CH₂COOH — and the saturated CH₂ at 2940 cm⁻¹ confirms it. Phenylacetic acid.

Hardware: how a modern FTIR works

The heart of any FTIR is a Michelson interferometer. A broadband IR source (a heated SiC ceramic, ~1300 K) sends light through a beamsplitter; half goes to a fixed mirror, half to a moving mirror; the recombined beam carries an interference pattern that depends on the moving-mirror position. Pass the beam through the sample, detect the resulting modulated intensity, and apply a Fourier transform to recover the spectrum.

  • Source. Globar (silicon carbide rod) for mid-IR, tungsten for near-IR.
  • Beamsplitter. KBr-coated Ge for mid-IR; CaF₂ for near-IR.
  • Detector. DTGS (deuterated triglycine sulfate) for routine work; MCT (mercury–cadmium–telluride) cooled to 77 K for high-sensitivity microscopy.
  • Sampling accessory. ATR with diamond crystal is the modern default. Transmission cells (KBr, CaF₂ windows) for quantitative work. Diffuse-reflectance (DRIFTS) for powders. Specular reflectance for thin films on metal.

Real-world applications

  • Pharmaceutical identification. The US Pharmacopeia and European Pharmacopeia accept FTIR-ATR as a primary identification method. A 30-second ATR scan of an incoming raw material is matched against the supplier's reference spectrum at > 95% correlation before release.
  • Polymer recycling. Sorting facilities use NIR spectroscopy to distinguish PET, HDPE, PVC, LDPE, PP, PS at conveyor-belt speeds (5 m/s, 100 ms per particle). The diagnostic NIR overtones of the C–H, O–H and C=O groups separate every common consumer plastic.
  • Atmospheric monitoring. The IASI satellite payload measures CO, CO₂, CH₄, O₃, N₂O and water vapour profiles globally with FTIR at 0.5 cm⁻¹ resolution. Each rotational-vibrational line is fit against pressure and temperature.
  • Forensic drug ID. ATR-FTIR identifies seized cocaine, heroin, amphetamines and synthetic cannabinoids at trafficking levels in seconds. Field-deployable units with reference libraries replace bulky benchtop GC-MS in many roadside stops.
  • Art conservation. Non-contact reflectance FTIR maps pigments, binders and varnishes on canvases and frescoes without sampling. Indigo at 1180 cm⁻¹, lead white at 1410 cm⁻¹, oil binder by C=O at 1740 cm⁻¹.
  • Process analytical technology (PAT). In-line FTIR probes immersed in pharmaceutical reactors monitor reaction progress in real time — no aliquoting, no quenching. The shift of a starting-material C=O to a product C=O is the kinetic signal.

Common mistakes and pitfalls

  • Calling every broad ~3300 cm⁻¹ band an alcohol. It might be a carboxylic acid (broader, lower), a primary amine (twin peaks), or just adsorbed water — check for corroborating bands.
  • Ignoring CO₂ and water-vapour bands. CO₂ at 2350 cm⁻¹ and rotational H₂O lines at 1500–2000 and 3500–4000 cm⁻¹ leak in from atmosphere. Subtract a fresh background; purge the bench with N₂ for low-noise work.
  • Trusting peak position to ±1 cm⁻¹. Hydrogen bonding, concentration, solvent and temperature can move bands by 5–30 cm⁻¹. Match to ranges, not point values.
  • Forgetting the ATR depth dependence. The evanescent wave penetrates ~1 µm at 1500 cm⁻¹ but only ~0.4 µm at 4000 cm⁻¹. Bands at higher wavenumber appear weaker than in transmission spectra; ATR-correction algorithms compensate.
  • Quantifying without Beer's law check. IR transmittance is non-linear; concentration plots use absorbance A = log₁₀(I₀ / I) and only stay linear up to A ≈ 1.5. Above that the detector saturates and your calibration curves bend.
  • Assigning fingerprint-region peaks individually. Below 1500 cm⁻¹ the spectrum is dense and bands are coupled. Use it for compound matching, not for piecewise functional-group assignment.
  • Confusing transmittance and absorbance scales. Old papers plot %T (peaks point down); modern software plots A (peaks point up). Mistaking one for the other reverses every intensity comparison.

Frequently asked questions

Why is the unit cm⁻¹ rather than nm or Hz?

Wavenumber, ν̃ = 1 / λ in centimetres, is proportional to photon energy and convenient for the mid-IR range. A wavenumber of 1700 cm⁻¹ corresponds to 5.88 µm wavelength and 51 THz frequency — but 1700 fits on a spectrum axis without scientific notation, and energy differences between bands map linearly to differences in wavenumber. The mid-IR runs roughly from 4000 to 400 cm⁻¹.

Why does the carbonyl band move with substitution?

C=O stretching frequency tracks bond order and electronic environment. Aldehydes and saturated ketones land at ~1715 cm⁻¹. Esters shift up to ~1740 cm⁻¹ because the alkoxy oxygen donates and the carbonyl gains slight double-bond character. Amides drop to ~1680 cm⁻¹ because nitrogen lone-pair donation weakens the C=O. Conjugation lowers the band by 20–40 cm⁻¹ — α,β-unsaturated ketones at 1675 cm⁻¹. The pattern is so reliable that experienced spectroscopists distinguish aldehyde, ester, amide and acid by carbonyl position alone.

What is the fingerprint region?

The 1500–400 cm⁻¹ stretch of an IR spectrum, where coupled C–C, C–O and C–N skeletal vibrations produce a dense, molecule-specific pattern. It's hard to assign individual bands here but easy to compare the whole region against a library: two compounds with identical fingerprints are essentially the same molecule. Forensic and pharmaceutical labs match unknowns to reference spectra primarily by fingerprint-region overlay.

Why does water ruin IR spectra?

Liquid water absorbs strongly across the entire mid-IR — broad bands at 3400 cm⁻¹ (O–H stretch), 1640 cm⁻¹ (H–O–H bend) and a continuum elsewhere. A 25 µm pathlength of water completely blocks transmission. ATR-FTIR partially solves this because the evanescent wave only samples ~1 µm of solution; even so, biological samples typically use D₂O instead, which shifts those bands to 2500 and 1210 cm⁻¹ and clears the protein amide window.

What's the difference between IR and Raman spectroscopy?

IR measures absorption of infrared photons by vibrations that change the molecular dipole moment. Raman measures inelastic scattering of visible-laser photons by vibrations that change polarisability. The two are complementary: symmetric stretches like C=C in ethylene are weak in IR but strong in Raman; polar stretches like O–H are strong in IR but weak in Raman. Aqueous samples favour Raman (water has weak Raman scattering); air-sensitive samples favour Raman (no need for specialised cells); fibrous solids favour IR-ATR (no laser, no fluorescence).

Why does ATR not need sample preparation?

Attenuated total reflectance presses the sample against a high-refractive-index crystal (diamond, ZnSe or Ge). IR enters the crystal, totally internally reflects at the interface, but generates a brief evanescent wave that penetrates ~1 µm into the sample. That tiny path length means strongly-absorbing samples — neat liquids, polymers, powders, even rubber — give clean spectra without dilution, KBr pellets, or films. ATR is now the default sampling mode in most labs.

How does FTIR differ from dispersive IR?

Dispersive instruments sweep a grating across one wavelength at a time — slow and noisy. Fourier-transform IR uses a Michelson interferometer that encodes all wavelengths simultaneously into an interferogram; a fast Fourier transform converts that to a spectrum. The Fellgett (multiplex) advantage means a 30-second scan resolves bands that took an hour on a 1960s grating instrument. Modern FTIRs run at 1 cm⁻¹ resolution, 32-scan averaging, in under a minute.