Physical Chemistry
Lattice Energy
The energy released when gas-phase ions snap into a crystal
Lattice energy is the energy released when isolated gas-phase ions assemble into one mole of ionic crystal. It scales as U ∝ |z⁺z⁻|/r₀ — bigger charges and smaller ions mean stronger lattices. NaCl: −787 kJ/mol; MgO: −3795 kJ/mol. The Born–Landé equation computes it from Madelung constants and ionic radii; experimental values come from the Born–Haber cycle.
- Coulomb scalingU ∝ z⁺z⁻ / r₀
- NaCl−787 kJ/mol
- MgO−3795 kJ/mol
- Madelung (NaCl-type)1.7476
- Sign conventionNegative = exothermic formation
- Measured viaBorn–Haber cycle
Interactive visualization
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Watch the 60-second explainer
A condensed visual walkthrough — narrated, captioned, under a minute.
What lattice energy is
Imagine vaporising one mole of solid sodium chloride into a gas of separated Na⁺ and Cl⁻ ions, all infinitely far apart. That requires energy. The reverse process — letting those gas-phase ions fall together into the cubic crystal lattice — releases the same energy. That energy is the lattice energy U:
Na⁺(g) + Cl⁻(g) → NaCl(s) U = −787 kJ/mol
By the standard chemistry sign convention, U is negative because the formation step is exothermic. Some textbooks (notably older British ones) report the magnitude as positive, defining lattice energy as the endothermic dissociation step. Always check.
The size of U sets a great many physical properties. Crystals with very negative U are hard, refractory, and barely soluble. Salts with smaller-magnitude U dissolve in water, melt readily, and behave more like everyday table salt.
Coulomb's law as a starting point
The simplest model is two point charges separated by distance r₀:
U_pair = −k · z⁺z⁻ · e² / r₀
k = 1 / (4πε₀) = 8.988 × 10⁹ N·m²/C²
e = 1.602 × 10⁻¹⁹ C (elementary charge)
z⁺, z⁻ = ion charges (use absolute values; sign handled separately)
r₀ = sum of cation + anion radii
Two simple consequences fall out immediately. First, U scales linearly with the product of charges. Doubling both charges (from ±1 to ±2) quadruples U. Second, U scales inversely with distance. Smaller ions pack tighter and bind harder. Both rules are visible in the periodic table: across a row of an alkali halide table, fluorides (small) beat chlorides which beat bromides which beat iodides.
Worked example — NaCl from first principles
Compute the lattice energy of NaCl from the Born–Landé equation and compare to the measured −787 kJ/mol. Take r₀ = r(Na⁺) + r(Cl⁻) = 1.02 + 1.81 = 2.83 Å = 2.83 × 10⁻¹⁰ m. Madelung constant for the rock-salt structure is M = 1.7476. Born exponent n = 9 (average of 7 for Na⁺ and 9 for Cl⁻).
U = −(N_A · M · z⁺z⁻ · e²) / (4πε₀ · r₀) · (1 − 1/n)
N_A · e² / (4πε₀) = 1.389 × 10⁻⁴ J·m/mol (handy combined constant)
U = −(1.389 × 10⁻⁴) · (1.7476) · (1)(1) / (2.83 × 10⁻¹⁰) · (1 − 1/9)
= −(1.389 × 10⁻⁴ · 1.7476 / 2.83 × 10⁻¹⁰) · (0.889)
= −(8.578 × 10⁵ J/mol) · (0.889)
= −7.62 × 10⁵ J/mol
= −762 kJ/mol
Measured (via Born–Haber cycle): U_NaCl = −787 kJ/mol. The Born–Landé prediction is within 3.2% — remarkable for a model whose only physics is Coulomb's law and a one-parameter repulsive correction. The remaining discrepancy comes from neglected dispersion forces and the assumption of perfectly spherical ions.
For MgO with z⁺ = +2, z⁻ = −2, r₀ = 2.10 Å, the same machinery gives roughly U ≈ −3923 kJ/mol against measured −3795 kJ/mol — about 3% high. The pattern holds across hundreds of ionic crystals.
Lattice-energy specs
| Compound | Lattice energy (kJ/mol) | m.p. (°C) | Solubility (g/L, 25 °C) | Use |
|---|---|---|---|---|
| LiF | −1030 | 848 | 2.7 | Optics, glassware |
| NaF | −910 | 993 | 40 | Toothpaste additive |
| NaCl | −787 | 801 | 360 | Table salt, deicer |
| NaBr | −747 | 747 | 905 | Drilling fluid, sedative |
| NaI | −704 | 661 | 1840 | Scintillator crystals |
| MgO | −3795 | 2852 | 0.0086 | Refractory bricks, antacid |
| CaO | −3414 | 2613 | 1.19 (reactive) | Cement, steel making |
| Al₂O₃ | −15,916 | 2072 | ~0 | Sapphire, abrasives |
The Al₂O₃ value reflects the multiplicity: five ions per formula unit, with charges +3 and −2. Lattice energies of trivalent oxides explain why aluminium and chromium oxides form the protective passivation layers that make stainless steel and aluminium cookware corrosion-resistant.
Madelung sum visualisation
NaCl rock-salt structure (cubic)
●───○───● ● = Na⁺
│ │ │ ○ = Cl⁻
○───●───○ Pair distance r₀
│ │ │
●───○───●
Madelung sum at central Na⁺:
+6 × (−1/r₀) nearest neighbours (Cl⁻ at r₀)
+12 × (+1/(r₀√2)) next-nearest (Na⁺ at r₀√2)
+8 × (−1/(r₀√3)) third shell (Cl⁻ at r₀√3)
+ ...
Sum (after geometric convergence): M = 1.7476
Lattice energy estimation methods
| Born–Landé | Born–Mayer | Kapustinskii | Born–Haber (experimental) | |
|---|---|---|---|---|
| Form | Coulomb · (1 − 1/n) | Coulomb · (1 − ρ/r₀) | Coulomb · 1.21·10⁵·z⁺z⁻·ν / r₀ | Sum of measured ΔH steps |
| Need crystal structure? | Yes (M from geometry) | Yes | No (ν = ions per formula) | No |
| Repulsion model | r⁻ⁿ (Born exponent) | e^(−r/ρ) (Buckingham) | Empirical correction | — |
| Typical accuracy | ±3–5% | ±2–3% | ±5–10% | ±0.5% |
| Strength | Transparent physics | Better at short r₀ | Works for unknown structures | Direct, structure-free |
| Weakness | Ignores dispersion, polarisability | Same | Empirical | Needs all sub-step ΔHs |
Variants and refinements
- Kapustinskii equation. When you don't know the crystal structure, use U ≈ 1.21 × 10⁵ · ν · z⁺z⁻ / (r⁺ + r⁻) kJ/mol·Å, where ν is the number of ions per formula unit. Works to ~10% for any new ionic compound.
- Born–Mayer refinement. Replaces the 1/n repulsive term with an exponential, fitting compressibility data better. The two parameters (e^(−r/ρ)) usually give a percent better than Born–Landé.
- Polarisability corrections. Real ions are not perfectly spherical; high-charge cations distort anions. Adding a London-dispersion term (the Mayer correction) tightens predictions for "soft" ions like Cs⁺ or I⁻.
- Modern DFT calculations. Periodic density-functional theory computes lattice energies from electronic structure, achieving ±1% accuracy for simple binary compounds and serving as a benchmark for the analytic equations.
- Madelung-constant catalogue. Each lattice type has its own M: NaCl 1.7476, CsCl 1.7627, ZnS (zincblende) 1.6381, fluorite 2.5194, rutile 2.408. Different M values explain why CaF₂ is so much more stable than CaCl₂.
Common pitfalls
- Sign-convention confusion. Some textbooks report U as positive (energy needed to break the lattice), others as negative (energy released when it forms). Always confirm before comparing values across sources.
- Ignoring the charge product. Students often quote "smaller ions = bigger lattice energy" but forget that doubling charges has roughly four times the effect of halving the radius. CaO beats LiF for both reasons.
- Forgetting that ionic radii are model-dependent. Shannon, Pauling, and Goldschmidt radii differ by ~10%. The same Born–Landé calculation can change by 5% depending on which set you use — quote the source.
- Comparing ionic and covalent solids on the same scale. Lattice energy is well-defined only for predominantly ionic compounds. AgI and HgS have substantial covalent character; their measured "lattice energies" diverge wildly from Born–Landé predictions because the model assumption fails.
- Forgetting that lattice energy is a thermodynamic state function, not an experimental observable. You can't put NaCl in a calorimeter and read off −787 kJ/mol directly. The Born–Haber cycle backs it out from independently measured quantities — and any error in those quantities propagates.
- Mistaking Madelung sums for simple geometric series. The lattice sum is conditionally convergent — different summation orders give different "answers" until you use Ewald-style techniques. The 1.7476 figure is the regularised result.
Frequently asked questions
What is lattice energy?
The energy change when one mole of gas-phase ions assembles into a solid ionic lattice. By the chemistry sign convention it is negative (energy released): for NaCl, U = −787 kJ/mol. Some textbooks define it as the magnitude (positive) for the reverse process — always check sign convention before comparing values.
Why does MgO have a much larger lattice energy than NaCl?
Coulomb's law: U ∝ |z⁺z⁻|/r₀. NaCl has charges of +1 and −1 (product 1) at r₀ ≈ 2.82 Å. MgO has charges of +2 and −2 (product 4) at r₀ ≈ 2.10 Å. The product of charges is 4× larger and the distance ~25% shorter — together giving roughly 4 × (2.82/2.10) ≈ 5× more lattice energy. Experimental ratio: 3795/787 ≈ 4.8.
What is the Madelung constant?
A geometric sum that adds up the Coulomb potential at one ion contributed by every other ion in an infinite crystal. For NaCl-structure crystals M = 1.7476; CsCl is 1.7627; fluorite is 2.5194. It depends only on the lattice geometry, not on the specific ions. Larger M means more efficient packing of opposite charges.
What is the Born–Landé equation?
U = −N_A · M · z⁺z⁻ · e² / (4πε₀ · r₀) · (1 − 1/n). It computes lattice energy from first principles using the Madelung constant M, ion charges, distance r₀, and the Born exponent n (≈ 9 for NaCl, accounting for short-range repulsion). For NaCl this predicts U ≈ −766 kJ/mol against the measured −787 kJ/mol — a 3% match.
How is lattice energy measured?
Indirectly, via the Born–Haber cycle. You add up the energy steps that take a metal element and a non-metal molecule through atomization, ionization, electron affinity, and lattice formation, equating the total to the experimentally measured enthalpy of formation. Lattice energy emerges as the unknown that closes the cycle.
Why does lattice energy correlate with melting point and solubility?
Higher lattice energy means more energy needed to break the crystal apart. So MgO (−3795 kJ/mol) melts at 2852 °C and is essentially insoluble in water; NaCl (−787 kJ/mol) melts at 801 °C and dissolves freely. The trade-off with hydration enthalpy explains solubility — hydration must outweigh lattice breaking for the salt to dissolve.