Periodic Chemistry
Spectrochemical Series
How the ligand you bolt onto a metal decides its color and its magnetism
The spectrochemical series ranks ligands by how strongly they split a transition metal's d-orbitals. The size of that splitting, Δ, fixes the wavelength a complex absorbs — and therefore its color — and decides whether it is high-spin or low-spin.
- What it ranksLigand field strength
- Key quantityΔo (10 Dq)
- Typical Δo100 – 400 kJ/mol
- DecidesColor + spin state
- Weak → strongI⁻ … H₂O … CN⁻ < CO
Interactive visualization
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Watch the 60-second explainer
A condensed visual walkthrough — narrated, captioned, under a minute.
The idea: ligands tune the d-orbital gap
Drop a bare transition-metal ion in space and its five d-orbitals all have the same energy — they are degenerate. Surround it with six ligands at the corners of an octahedron and that degeneracy breaks. The two orbitals that point straight at the ligands (dz² and dx²−y², together called the eg set) feel more electron–electron repulsion and rise in energy. The three orbitals that point between the ligands (dxy, dxz, dyz, the t2g set) drop. The energy gap between them is the crystal-field splitting, Δo (also written 10 Dq).
Here is the punchline the spectrochemical series captures: the size of Δo depends almost entirely on which ligand you use. Swap chloride for ammonia on the same metal in the same oxidation state and Δo jumps. Swap ammonia for cyanide and it jumps again. Rank every common ligand by the Δo it produces and you get a single, nearly metal-independent ordering — the spectrochemical series:
WEAK FIELD ← small Δo large Δo → STRONG FIELD
I⁻ < Br⁻ < S²⁻ < SCN⁻ < Cl⁻ < NO₃⁻ < F⁻ < OH⁻ < ox²⁻ < H₂O
< NCS⁻ < CH₃CN < NH₃ < en < bipy < phen < NO₂⁻ < CN⁻ < CO
π-DONORS σ-only π-ACCEPTORS
(push Δo down) (neutral) (push Δo up)
That single line of ligands explains a huge fraction of inorganic color and magnetism. Everything downstream — which wavelength a complex absorbs, what color you see, how many unpaired electrons it carries — falls out of where its ligands sit on this scale.
Why the order is what it is: σ, π-donation, π-back-bonding
Pure electrostatics (the original crystal-field picture) gets the rough trend but fails on the details — it cannot explain why neutral CO outsplits the F⁻ anion. The modern explanation is the molecular-orbital ligand-field model, in which three effects feed into Δo:
- σ-donation. A ligand's lone pair points at the eg orbitals and pushes them up. Stronger σ-donors → larger Δo. This is why NH₃ (good σ-donor) beats H₂O.
- π-donation (weak-field end). Halides and oxygen donors have filled p or lone-pair orbitals of π symmetry. These push the t2g set up, shrinking the gap. The heavier the halide, the more diffuse and the stronger the π-donation: I⁻ > Br⁻ > Cl⁻ > F⁻ — exactly the weak-field tail of the series.
- π-back-bonding (strong-field end). CO, CN⁻, NO₂⁻ and phenanthroline carry empty π* orbitals. The filled metal t2g donates electron density into them, which lowers t2g and enlarges Δo. This single effect is why the strong-field champions are π-acceptors, not the most negatively charged ligands.
So the series reads left-to-right as: π-donors (Δ down) → σ-only donors (neutral) → π-acceptors (Δ up). Reading the position of a ligand tells you its bonding character at a glance.
From Δ to the color you see
A d–d transition promotes one electron from t2g to eg. The photon it absorbs has exactly the energy Δo:
Δo = h·c / λ → λ_absorbed = h·c / Δo
The complex looks like the complement of the color it absorbs. A complex that absorbs orange light (~600 nm) looks blue; one that absorbs blue–violet (~430 nm) looks yellow-orange. So as a ligand climbs the series:
- Δo rises → absorbed photon is more energetic → λabsorbed shifts toward the blue (shorter wavelength).
- The observed color shifts the opposite way.
The classic teaching set is the same metal with a ligand walk-up. [Cr(H₂O)₆]³⁺ absorbs around 575 nm and looks violet; replace water with the stronger-field ethylenediamine to make [Cr(en)₃]³⁺ and Δo rises, the absorption moves toward ~455 nm, and the complex turns yellow. Same metal, same oxidation state — only the ligand changed, and the color tracked the spectrochemical series exactly.
High-spin vs low-spin: Δ competes with the pairing energy
For octahedral d⁴ through d⁷ configurations there is a genuine fork. The first three electrons go into the three t2g orbitals singly (Hund's rule). The fourth electron has two options:
Option A — pair up inside t2g cost = P (pairing energy)
Option B — go up to the empty eg cost = Δo (the splitting)
if Δo < P → electron climbs to eg → HIGH-SPIN (max unpaired e⁻)
if Δo > P → electron pairs in t2g → LOW-SPIN (min unpaired e⁻)
The pairing energy P — the extra electrostatic and exchange cost of forcing two electrons into one orbital — runs roughly 200–300 kJ/mol for first-row metals. Weak-field ligands keep Δo below that and you get high-spin; strong-field ligands push Δo above it and you get low-spin. The spectrochemical series is therefore also a high-spin / low-spin predictor: anything left of about H₂O tends to be high-spin, anything from NH₃ rightward (especially CN⁻, CO) tends to be low-spin.
The textbook pair is iron(II), d⁶. [Fe(H₂O)₆]²⁺ is high-spin with four unpaired electrons (paramagnetic, μ ≈ 5.1 μB); [Fe(CN)₆]⁴⁻ is low-spin with zero unpaired electrons (diamagnetic). Identical metal, identical charge, opposite magnetism — decided entirely by where the ligand sits on the series.
Ligand-by-ligand data
Real Δo values, mostly referenced to a common metal so the trend is clean. (1000 cm⁻¹ ≈ 11.96 kJ/mol.)
| Complex | Ligand class | Δo (cm⁻¹) | Δo (kJ/mol) | Spin / color |
|---|---|---|---|---|
| [CrCl₆]³⁻ | π-donor (weak) | ~13,600 | ~163 | high-spin, green |
| [Cr(H₂O)₆]³⁺ | σ + weak π-donor | 17,400 | 208 | high-spin, violet |
| [Cr(NH₃)₆]³⁺ | σ-donor | 21,600 | 258 | yellow |
| [Cr(en)₃]³⁺ | chelating σ-donor | 21,900 | 262 | yellow |
| [Cr(CN)₆]³⁻ | π-acceptor (strong) | 26,600 | 318 | yellow |
| [Co(H₂O)₆]²⁺ | weak field, d⁷ | 9,300 | 111 | high-spin, pink |
| [Co(NH₃)₆]³⁺ | strong field, d⁶ | 22,900 | 274 | low-spin, orange |
| [Fe(CN)₆]³⁻ | π-acceptor, d⁵ | ~35,000 | ~419 | low-spin, red |
Two patterns jump out. First, on the same metal (Cr³⁺), Δo climbs monotonically from Cl⁻ → H₂O → NH₃ → en → CN⁻, exactly tracing the series. Second, oxidation state matters enormously: Co(II) with water gives Δo ≈ 111 kJ/mol (high-spin), while Co(III) — only one electron different in charge — with the moderate ligand ammonia reaches 274 kJ/mol and goes low-spin.
The numbers that make it click
A few quantitative anchors worth carrying around:
- The visible window in Δ. Visible light spans roughly 400–700 nm, i.e. photon energies of ~170 to ~300 kJ/mol. That is exactly the Δo range of common first-row complexes — which is why transition-metal complexes are the showcase of inorganic color. A Δo of 240 kJ/mol corresponds to λ ≈ 500 nm.
- [Ti(H₂O)₆]³⁺, the cleanest case. A single d-electron, one absorption band at λmax ≈ 500 nm. That band is Δo: 20,300 cm⁻¹ ≈ 243 kJ/mol. The complex absorbs green and looks purple.
- Metal-row scaling. Δ rises about 50% per row going down a group. For the same ligands, Δ(4d) ≈ 1.5 × Δ(3d) and Δ(5d) ≈ 1.5 × Δ(4d). Combined with higher oxidation states, this is why 4d/5d metals (Rh³⁺, Pd²⁺, Pt²⁺, Ir³⁺) are almost universally low-spin.
- Oxidation-state scaling. Δo(M³⁺) ≈ 1.5 × Δo(M²⁺) for the same metal and ligands. Higher charge pulls ligands closer, increasing repulsion at the eg orbitals.
- Crystal-field stabilization energy (CFSE). Each t2g electron sits 0.4 Δo below the barycenter; each eg electron sits 0.6 Δo above it. Low-spin d⁶ (all six in t2g) has CFSE = −2.4 Δo — the most stable configuration possible, which is why low-spin d⁶ ions like Co³⁺ and Pt⁴⁺ are kinetically inert.
Where it shows up
- Hemoglobin and the breath you just took. Deoxyhemoglobin's iron is high-spin Fe(II) bound to a weak-field histidine and porphyrin. When O₂ binds it acts as a moderately strong π-acceptor, the iron flips to low-spin, shrinks slightly, and slips into the porphyrin plane — the conformational trigger that drives cooperative oxygen uptake. The high-spin/low-spin switch literally moves your blood.
- Cobalt's classic color change. Pink [Co(H₂O)₆]²⁺ (weak field) turns deep blue [CoCl₄]²⁻ (tetrahedral, even smaller Δ) on adding concentrated HCl — the basis of cobalt-chloride humidity indicators and "invisible ink."
- Prussian blue and Hexacyanoferrates. The intense blue of [Fe(CN)₆]-based pigments comes from CN⁻ being the second-strongest field ligand, giving low-spin iron and strong metal-to-metal charge transfer.
- Gemstones. Ruby is Cr³⁺ doped into Al₂O₃; the oxide lattice sets Δo so that Cr³⁺ absorbs in the yellow-green and transmits red. Emerald is the same Cr³⁺ ion in beryl, where a slightly weaker field shifts the absorption and the gem turns green. Same chromophore, different ligand field, different jewel.
- Spin-crossover materials. Iron(II) complexes engineered so Δo ≈ P flip between high- and low-spin with temperature, pressure, or light — candidate switches for molecular memory and thermochromic coatings.
Octahedral vs tetrahedral splitting
| Octahedral (Δo) | Tetrahedral (Δt) | |
|---|---|---|
| Coordination number | 6 | 4 |
| Lower set | t2g (3 orbitals) | e (2 orbitals) |
| Upper set | eg (2 orbitals) | t2 (3 orbitals) |
| Splitting size | baseline | Δt ≈ (4/9) Δo |
| Ligand orientation | point straight at orbitals | point between orbitals |
| Typical spin state | high- or low-spin | almost always high-spin |
| Δ vs pairing energy | can exceed P | Δt < P essentially always |
Because no tetrahedral ligand points directly at a d-orbital and there are only four of them, Δt is roughly four-ninths of the octahedral value for the same metal and ligands. That value sits below the pairing energy in essentially every real case, which is why low-spin tetrahedral complexes are vanishingly rare — a clean, memorable consequence of the geometry-scaled spectrochemical splitting.
Common misconceptions and pitfalls
- "More negative charge means stronger field." No. If charge were the driver, F⁻ would outsplit neutral CO and NH₃ — it doesn't. π-back-bonding by neutral π-acceptors dominates the strong-field end. Charge is a weak predictor; bonding type is the real one.
- "The color is the wavelength absorbed." The opposite. You see the complement of the absorbed band. A complex that absorbs orange looks blue, not orange.
- "The series predicts the metal's spin no matter what." The ligand sets Δo, but the spin outcome only forks for d⁴–d⁷. d¹–d³ and d⁸–d¹⁰ have no high/low-spin ambiguity in octahedral fields — there is only one way to fill them.
- "Δo is fixed for a ligand." The order is nearly constant, but the magnitude scales with the metal's identity, row, and oxidation state. Quote Δo for a specific complex, never for a ligand alone.
- "Crystal-field theory explains the whole series." Purely electrostatic CFT gets the trend but misplaces π-acceptors. You need ligand-field / MO theory to explain CO and CN⁻ at the top.
- "Strong-field always means intensely colored." Not necessarily. Strong-field, low-spin complexes can be pale if their d–d transitions are Laporte- or spin-forbidden; the most intense colors often come from charge-transfer bands, not d–d transitions at all (e.g. deep purple permanganate, which has no d-electrons to split).
Frequently asked questions
Why does the spectrochemical series put CO and CN⁻ above NH₃ even though they are weaker σ-donors?
Because the splitting Δ is not set by σ-donation alone. CO and CN⁻ have empty π* orbitals that accept electron density back from the filled metal t2g set. This π-back-bonding lowers the t2g orbitals and raises Δ, pushing both ligands to the strong-field end. The full electrostatic crystal-field picture cannot explain their position; you need the molecular-orbital ligand-field model, where σ-donor strength, π-donation, and π-acceptance all feed into Δ.
How does the size of Δ decide high-spin versus low-spin?
Electrons fill the lower t2g set first. The fourth d-electron in an octahedral d⁴–d⁷ complex faces a choice: pair up in t2g (costing the pairing energy P, about 200–300 kJ/mol) or jump to the higher eg set (costing Δo). If Δo < P the electron goes up — high-spin, more unpaired electrons. If Δo > P it pairs — low-spin. Strong-field ligands push Δo above P; weak-field ligands leave it below.
Why is [Fe(H₂O)₆]³⁺ nearly colorless while [Fe(CN)₆]³⁻ is deep red?
Water is a weak-field ligand, so [Fe(H₂O)₆]³⁺ is high-spin d⁵ with every d-orbital singly occupied. Every possible d–d transition flips a spin, which is spin-forbidden, so absorption is extremely weak and the complex is pale violet to nearly colorless. CN⁻ is strong-field, making [Fe(CN)₆]³⁻ low-spin, which allows spin-allowed transitions and intense charge-transfer bands — hence the strong red color.
Does the spectrochemical series order change with the metal?
The ligand ordering is remarkably constant, but the absolute size of Δ depends strongly on the metal. Δ rises by about 50% on each step down a group (3d → 4d → 5d) and increases sharply with oxidation state: Δo for a +3 ion is roughly 1.5× that of the +2 ion. This is why second- and third-row transition metals are almost always low-spin even with moderate ligands.
What is the difference between Δo and Δt?
Δo is the octahedral splitting between the lower t2g and upper eg sets; Δt is the tetrahedral splitting, which inverts the pattern (lower e, upper t2). For the same metal and ligands, Δt ≈ (4/9)Δo because there are only four ligands and none point directly at a d-orbital. Δt is almost always smaller than the pairing energy, which is why tetrahedral complexes are virtually always high-spin.
How do you measure Δo experimentally?
Record the UV–vis absorption spectrum. The wavelength λmax of the d–d band gives Δo directly through Δo = hc/λ. For [Ti(H₂O)₆]³⁺, λmax ≈ 500 nm corresponds to Δo ≈ 240 kJ/mol (about 20,300 cm⁻¹). For complexes with more than one d-electron the analysis uses a Tanabe–Sugano diagram, but the principle is the same: the color band you see is a direct readout of the orbital splitting.