Manufacturing
Sheet Metal Bending
Why a bent part springs back a little
Sheet metal bending is a forming process that plastically deforms a flat blank into a permanent angle, usually by driving a punch into a V-die on a press brake. The bend stretches the outer fibres and compresses the inner ones about a neutral axis, so the flat-pattern length is never just the sum of the legs — it differs by a bend allowance set by the K-factor. And because only the surface truly yields while the core stays elastic, the part recovers a few degrees when released. That recovery is springback, and the entire craft of bending comes down to overbending precisely enough to cancel it.
- Air-bend forceP ≈ 650·UTS·t² / V
- Bend allowanceBA = (π/180)·A·(R + K·t)
- K-factor range0.33 – 0.50
- Typical springback (mild steel)1° – 3°
- Min inside radius~0.5 – 1.0 × t (ductile)
- Optimal V-die width8 × t (air bend)
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What happens inside the bend
Clamp a flat strip between a punch and a V-die and press. The metal directly under the punch tip wraps to a radius, and across the thickness of that wrapped zone the strain varies linearly: the outer surface is stretched in tension, the inner surface is compressed, and somewhere in between sits a fibre that changes length not at all — the neutral axis. As long as the strain at the surfaces stays below the elastic limit, the metal springs flat the instant you lift the punch. To make a permanent angle you must push the surface strain past yield so that part of the cross-section deforms plastically.
But yielding the surface does not yield the whole thickness. The strain falls to zero at the neutral axis, so a band of material around the centre never exceeds its elastic limit. When the punch retracts, that elastic core unloads like a released spring and partially straightens the bend. The bend angle opens up; the inside radius grows. This is springback, and it is unavoidable in any room-temperature bend — the only question is how much, and how to plan for it.
The neutral axis and the K-factor
The neutral axis does not sit at the geometric centre of the thickness. Because tension and compression are not symmetric — the outer fibres stretch farther than the inner fibres compress — the neutral axis migrates toward the inside of the bend. Its position is expressed as the K-factor: the distance from the inside surface to the neutral axis, as a fraction of thickness.
K = d_na / t
d_na = distance from inside surface to neutral axis (mm)
t = material thickness (mm)
K ≈ 0.33 for tight radii (R/t < 1)
K ≈ 0.50 for generous radii (R/t > 5)
K matters because it sets the bend allowance — the length of neutral-axis arc swallowed by the bend. Get K wrong and your flat blank comes out the wrong length, the legs end up short or long, and every hole punched in the flat lands in the wrong place after forming.
Bend allowance (arc length of neutral axis):
BA = (π / 180) · A · (R + K·t)
Bend deduction (how much shorter the flat is than leg-to-leg):
BD = 2·(R + t)·tan(A/2) − BA
Flat length:
L_flat = leg_1 + leg_2 − BD
A = bend angle (degrees)
R = inside bend radius (mm)
t = thickness (mm)
Springback, quantified
Springback can be derived from the elastic unloading of the bent section. A common closed-form estimate relates the final radius R_f to the loaded radius R_i:
R_i / R_f = 4 (R_i σ_y / E t)³ − 3 (R_i σ_y / E t) + 1
R_i = inside radius under load (mm)
R_f = inside radius after release (mm)
σ_y = yield strength (MPa)
E = Young's modulus (MPa)
t = thickness (mm)
The key grouping is σ_y / E. Springback grows when yield strength is high and modulus is low, because a stiff, low-yield material stores more recoverable elastic strain per unit of plastic strain. That single ratio explains the workshop folklore: aluminium springs back far more than steel even though it is "softer." Aluminium 6061-T6 has σ_y ≈ 275 MPa and E ≈ 69 GPa (σ_y/E ≈ 0.0040); mild steel has σ_y ≈ 250 MPa and E ≈ 200 GPa (σ_y/E ≈ 0.00125). The aluminium ratio is about three times larger, and so is its springback.
Overbending — the practical fix
Because springback opens the angle, the cure is to close it further during forming. To finish a 90° included angle with 2° of springback, the punch drives the metal to an 88° included angle; on release it relaxes the 2° back to 90°. The overbend angle is whatever cancels the measured springback for that exact material, thickness, radius and tooling combination — which is why production shops keep empirical bend tables rather than trusting a formula. A typical CNC press brake controller stores a springback offset per tool and per material and adjusts the ram depth automatically.
| Method | Air bending | Bottoming | Coining |
|---|---|---|---|
| Punch reaches die bottom? | No — stops short | Yes — touches die faces | Yes — squeezes bend zone |
| Angle set by | Ram depth | Die angle | Die angle + pressure |
| Inside radius set by | V-die opening (~0.16·V) | Punch nose radius | Punch nose radius |
| Springback | Highest (1–3°+) | Low (<1°) | Near zero |
| Relative force | 1× (baseline) | 3–5× | 5–8× |
| Tooling cost | Low, flexible | Medium | High, matched dies |
| Best for | Prototyping, varied angles | Repeatable production angles | Tight tolerance, thin gauge |
Worked example: bending force on a press brake
How much tonnage to air-bend a 1 m long, 2 mm mild-steel part in a 16 mm V-die? Use the standard air-bend force formula:
P = (650 · UTS · t²) / V (force per metre, in N/mm of bend length)
UTS = 450 MPa (mild steel, ~S275)
t = 2 mm → t² = 4 mm²
V = 16 mm (die opening, ~8× t)
P = (650 × 450 × 4) / 16
= 1,170,000 / 16
= 73,125 N per metre
≈ 73 kN/m
≈ 7.5 tonne over the 1 m bend
Widening the die to a 20 mm opening drops the force to about 59 kN/m, but the inside radius grows from roughly 0.16·16 ≈ 2.6 mm to 0.16·20 ≈ 3.2 mm. Force, radius and springback all trade against one another, which is why die selection is the first decision a brake operator makes.
Worked example: flat-pattern length
An L-bracket has two 50 mm legs, a 90° bend, an inside radius R = 3 mm in t = 2 mm steel, with K = 0.42. What length of flat stock do you need?
Bend allowance:
BA = (π/180) · 90 · (3 + 0.42 × 2)
= 1.5708 × (3 + 0.84)
= 1.5708 × 3.84
= 6.03 mm
Bend deduction:
BD = 2·(R + t)·tan(A/2) − BA
= 2·(3 + 2)·tan(45°) − 6.03
= 2 × 5 × 1.0 − 6.03
= 10 − 6.03
= 3.97 mm
Flat length:
L_flat = 50 + 50 − 3.97 = 96.03 mm
Cut the blank at 96 mm, not 100 mm. Use K = 0.50 by mistake and you would predict a 96.2 mm blank — only 0.2 mm off here, but the error compounds across a part with a dozen bends and turns a tolerance-perfect drawing into a pile of scrap.
Bend radius, grain and cracking
- Minimum inside radius. The outer fibre strain is roughly t / (2R + t). Push R too small and that strain exceeds the material's elongation limit, producing orange-peel texture and then cracks. Ductile mild steel and dead-soft aluminium bend to about 0.5–1.0× thickness; high-strength low-alloy steels need 1.5–3× and hardened alloys 3–4×.
- Grain direction. Rolled sheet has elongated grains. Bending across (perpendicular to) the rolling grain tolerates a tighter radius; bending along the grain cracks more readily because the stretched outer fibres run lengthwise through weak grain boundaries. Drawings often specify "bend across grain."
- Bend relief. A bend that ends at an edge tends to tear at the corner. A small relief notch at each end of the bend line stops the crack before it starts.
Failure modes and trade-offs
- Springback drift. Incoming material varies — a coil with 10% higher yield strength springs back more. Without per-coil offset, a batch that was dead-on at the start of the day creeps out of angle tolerance by the end.
- Outer-fibre cracking. Radius too tight, grain wrong, or material too hard. Anneal, increase the radius, or reorient the bend line.
- Die-mark scoring. The die shoulders drag across the part as it forms, leaving lines on the outside surface. Polished or urethane-insert dies, or a film between part and die, prevent this on cosmetic parts.
- Multi-bend interference. A later bend can collide with the flange formed by an earlier one. Bend sequence planning — usually working from the inside out — avoids the trap.
- Wrinkling near holes. A hole too close to the bend line distorts into an oval as the surrounding metal stretches. Keep holes at least 2.5× thickness plus the radius away from the bend.
- Over-coining cracks. Coining eliminates springback but the high local pressure can crack brittle or work-hardened material and accelerates tool wear; reserve it for thin, ductile, tight-tolerance parts.
Frequently asked questions
Why does bent sheet metal spring back?
Only the outer surface of a bend actually yields and stays plastically deformed; material near the neutral axis never exceeds its elastic limit. When you release the punch, that elastically strained core unloads and tries to straighten the part, opening the bend angle by a few degrees. The amount of springback grows with higher yield strength, larger bend radius relative to thickness, and lower Young's modulus — which is why a 1.5 mm 6061-T6 aluminium part springs back two to three times more than the same geometry in mild steel.
How do you compensate for springback?
The press brake overbends the part. To finish at a 90° included angle with 2° of springback, the punch drives the metal to 88° (an 88° included angle) so it relaxes back to 90° on release. Coining over-compresses the bend zone to lock the angle by yielding the material all the way through, and bottoming sets the angle against a matched die. Air bending, which never touches the die bottom, has the most springback and is usually trimmed empirically with a bend table for each material, thickness and tooling combination.
What is bend allowance and the K-factor?
Bend allowance is the arc length of the neutral axis through the bend; it tells you how much flat material a bend consumes. BA = (π/180)·A·(R + K·t), where A is the bend angle in degrees, R the inside radius, t the thickness and K the K-factor — the fraction of thickness from the inside surface to the neutral axis. K is typically 0.33 to 0.50, shifting toward the inside surface (smaller K) for tight radii because the outer fibres stretch more than the inner fibres compress.
What is the minimum bend radius for sheet metal?
The minimum inside radius is set by how much the outer fibre can stretch before it cracks. As a rule of thumb it scales with thickness: soft aluminium and mild steel bend down to about 0.5–1.0× thickness, while high-strength or hardened alloys may need 2–4× thickness. Bending across the rolling grain tolerates a tighter radius than bending along it, because elongated grains crack more readily when stretched lengthwise. Below the minimum radius the outer surface develops orange-peel texture and then tension cracks.
What's the difference between air bending, bottoming and coining?
Air bending stops the punch short of the die bottom, so the part contacts only the punch tip and the two die shoulders — angle is set by punch depth, the V-die opening controls the radius, and tonnage is low. Bottoming drives the part fully onto the die faces, fixing a repeatable angle with less springback at roughly 3–5× the air-bending force. Coining squeezes the bend zone hard enough to plastically yield it through the full thickness, nearly eliminating springback but demanding 5–8× the bottoming force and matched, hardened tooling.
How much force does a press brake bend need?
For air bending, the per-metre force is approximately P = (650 · UTS · t²) / V, where UTS is the ultimate tensile strength in MPa, t the thickness in mm and V the die opening in mm. A 1 m long bend of 2 mm mild steel (UTS ≈ 450 MPa) in a 16 mm V-die needs about 650·450·4/16 ≈ 73 kN/m, so roughly 7 tonnes for the metre. Widening the die opening lowers force but increases the bend radius; bottoming and coining multiply this figure several times over.