Mechanical

Thermal Expansion

Why heated materials grow — and why holding them still is dangerous

Thermal expansion is the tendency of a material to change its dimensions when its temperature changes, because heating widens the average spacing between atoms in the lattice. For a solid, the change in length follows ΔL = α·L·ΔT, where α is the coefficient of linear expansion (units 1/K), L is the original length, and ΔT is the temperature change. Area grows at about 2α and volume at about 3α. Engineering α values span from roughly 1.2 ×10⁻⁶ /K for Invar to about 23–25 ×10⁻⁶ /K for aluminium. When a heated part is fully restrained, the suppressed strain becomes thermal stress σ = E·α·ΔT — independent of length — which can buckle rails, crack castings, and pop welds. Designers absorb this movement with expansion joints, sliding bearings, and low-expansion alloys, and exploit the differential in bimetallic strips.

  • Linear lawΔL = α·L·ΔT
  • VolumeΔV ≈ 3α·V·ΔT
  • Restrained stressσ = E·α·ΔT (length-independent)
  • Steel α≈ 12 ×10⁻⁶ /K
  • Aluminium α≈ 23 ×10⁻⁶ /K
  • Invar α≈ 1.2 ×10⁻⁶ /K

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Why thermal expansion matters

Nearly every structure and machine on Earth sees a working temperature range far wider than most people assume. A steel bridge deck can sit at −20 °C on a clear winter night and reach +50 °C in direct summer sun; a jet-engine turbine disc swings from ambient to over 600 °C in seconds; a silicon die on a copper heat-sink cycles by tens of degrees every time a laptop wakes. Because the coefficient of linear expansion α of the materials involved almost never matches, those temperature swings turn into dimensional changes, relative motion, and — if the motion is blocked — enormous internal forces.

  • Civil structures. Bridges, rails, pipelines, and buildings must be free to grow and shrink, or must be deliberately restrained and designed for the resulting stress.
  • Precision machines. A coordinate-measuring machine or a lithography stepper drifts out of tolerance if its frame breathes with the room; metrology labs hold 20 °C to ±0.1 °C for exactly this reason.
  • Electronics packaging. Solder joints fatigue and crack because silicon (α ≈ 2.6 ×10⁻⁶ /K) is bonded to substrates and boards with much higher α — the coefficient-of-thermal-expansion (CTE) mismatch is a leading cause of chip-package failure.
  • Power and process plant. Steam pipes, boilers, and heat exchangers move centimetres as they warm; missing that motion snaps supports and nozzles.
  • Everyday sensing. The same effect that is a nuisance is also a feature: bimetallic strips turn temperature directly into mechanical motion for thermostats and breakers.

How it works, step by step

Thermal expansion is fundamentally about the shape of the interatomic potential well. If atoms sat in a perfectly symmetric (harmonic) well, heating would increase their vibration amplitude but not their average position, and there would be no expansion. Real bonds are anharmonic: the repulsive wall on the short-range side is steeper than the attractive tail on the long-range side. As temperature rises, atoms spend more time on the shallow far side, so the average spacing grows. Expansion is the macroscopic sum of that atomic-scale asymmetry.

  1. Start with free length. Take an unrestrained bar of original length L at reference temperature T₀.
  2. Raise temperature by ΔT. Each unit length grows by the fractional strain ε = α·ΔT, so the whole bar grows by ΔL = α·L·ΔT.
  3. Extend to area and volume. A square face of side L becomes (L + αLΔT)²; expanding and dropping the tiny (αΔT)² term gives ΔA ≈ 2α·A·ΔT. The same logic in three dimensions gives ΔV ≈ 3α·V·ΔT, so the volumetric coefficient β ≈ 3α for isotropic solids.
  4. Now block the motion. Clamp both ends so the bar physically cannot lengthen. The thermal strain still "wants" to occur, but the constraint forces a compensating mechanical strain of −α·ΔT.
  5. Read off the stress. By Hooke's law that mechanical strain implies a stress σ = E·(−α·ΔT), a compression of magnitude E·α·ΔT. Length has cancelled out entirely — a short stub and a long beam of the same material develop the same restrained stress for the same ΔT.
  6. Combine differentials. Bond two materials with different α (a bimetallic strip) and each layer is partly stretched and partly compressed to reconcile their lengths; the internal moment bends the strip toward the low-α side.

The governing equations, with every symbol defined:

ΔL = α · L · ΔT

σ = E · α · ΔT

  • ΔL — change in length (m)
  • L — original length at reference temperature (m)
  • α — coefficient of linear thermal expansion (1/K, i.e. per kelvin)
  • ΔT — temperature change, T − T₀ (K, numerically identical to °C for a difference)
  • σ — thermal (axial) stress when expansion is fully prevented (Pa); compressive when heated, tensile when cooled
  • E — Young's modulus of the material (Pa)

Coefficients of thermal expansion — reference values

Values below are approximate linear coefficients near room temperature; α itself rises slowly with temperature, so handbooks always quote a range. To convert a fractional strain into a temperature difference, remember 1 ×10⁻⁶ /K means one micrometre of growth per metre per kelvin.

Materialα (×10⁻⁶ /K)E (GPa)Restrained σ per 100 °C (MPa)
Invar (Fe–36Ni)1.2141≈ 17 (comp.)
Fused silica0.573≈ 3.7
Borosilicate glass3.364≈ 21
Silicon2.6170≈ 44
Titanium (Ti-6Al-4V)8.6114≈ 98
Glass (soda-lime)970≈ 63
Concrete10–1230≈ 33
Structural steel12200≈ 240
Stainless steel (304)17193≈ 328
Copper17117≈ 199
Brass19110≈ 209
Aluminium2369≈ 159

Two lessons jump out of the last column. First, restrained stress scales with the product E·α, not with α alone — aluminium expands nearly twice as much as steel yet builds less restrained stress because its modulus is far lower. Second, steel's E·α is high enough that a modest 100 °C rise generates ~240 MPa, comfortably past the yield strength of mild steel (~250 MPa), which is exactly why constrained steel structures buckle or yield rather than "just get a bit tight."

Worked example — a steel rail on a hot day

Consider a 25-metre length of continuous welded rail, structural steel with α = 12 ×10⁻⁶ /K and E = 200 GPa, installed at a neutral temperature of 25 °C and heated to a 55 °C rail-head temperature on a summer afternoon (ΔT = 30 K).

If it were free to move, its growth would be:

ΔL = α·L·ΔT = (12 ×10⁻⁶)(25 m)(30 K) = 9.0 ×10⁻³ m = 9.0 mm

Because it is clamped (continuous welded rail has no joints), that 9 mm cannot appear as motion, so it appears as compressive stress:

σ = E·α·ΔT = (200 ×10⁹)(12 ×10⁻⁶)(30) = 72 ×10⁶ Pa = 72 MPa compression

The corresponding compressive force in a rail of cross-section A ≈ 7,700 mm² is P = σ·A = (72 MPa)(7,700 mm²) ≈ 555 kN — over 55 tonnes pushing along the rail. This is why rail engineers install continuous welded rail at a controlled "rail neutral temperature," anchor sleepers heavily, and monitor for buckling ("sun kinks") on the hottest days: the stress is fixed by ΔT from neutral, but whether it produces a harmless squeeze or a lateral buckle depends on lateral track restraint.

Common misconceptions and failure modes

  • "Longer parts build more thermal stress." False — restrained σ = E·α·ΔT contains no length term. A long bar moves more if free, but a short and long bar of the same material reach the same stress if both are fully clamped.
  • "Only heating is a problem." Cooling a restrained member puts it in tension of the same magnitude, which is more dangerous for brittle materials like concrete and cast iron that are weak in tension.
  • "β equals α." The volumetric coefficient is ≈ 3α, and the area coefficient ≈ 2α. Mixing them up gives errors of 2–3× in fluid-expansion and gap-fit calculations.
  • "Water expands normally." Water is anomalous: between 0 and 4 °C it contracts as it warms (density peaks at 4 °C), which is why ice floats and lakes freeze top-down. Most CTE intuition from solids does not carry over to it.
  • "CTE mismatch only matters at high temperature." In electronics, a 40 °C swing across a silicon–copper interface fatigues solder over thousands of thermal cycles — Coffin–Manson low-cycle fatigue, not a single overstress.
  • "Glass breaks from heat, not from gradients." Thermal shock cracking comes from a temperature gradient: the hot inner surface expands against a cold outer skin, creating local tensile stress. Low-α borosilicate resists it far better than soda-lime glass.
  • "An expansion joint can be undersized a little." If the gap closes before the temperature peaks, the joint locks solid and the whole restrained stress slams back in — designers size the gap for the full expected ΔT plus installation tolerance.

Frequently asked questions

What is thermal expansion?

Thermal expansion is the tendency of a material to grow larger when heated and shrink when cooled, because higher temperature increases the average spacing between atoms in the lattice. For a solid rod the change in length is ΔL = α·L·ΔT, where L is the original length, ΔT is the temperature change, and α is the coefficient of linear expansion in units of 1/K (per kelvin). Most metals have α between 10 and 25 ×10⁻⁶ /K, so a 1-metre steel bar grows about 0.12 mm for every 10 °C rise.

What is the formula for thermal expansion?

Linear expansion: ΔL = α·L·ΔT. Area expansion: ΔA ≈ 2α·A·ΔT. Volume expansion: ΔV ≈ β·V·ΔT with β ≈ 3α for isotropic solids. Here α is the linear coefficient (1/K), L, A and V are the original length, area and volume, and ΔT is the temperature change in kelvin (or °C, since a temperature difference is the same in both scales). The 2α and 3α factors come from the binomial expansion of (1 + αΔT)² and (1 + αΔT)³, dropping second-order terms.

What is the coefficient of thermal expansion?

The coefficient of linear thermal expansion, α, is the fractional change in length per degree of temperature change: α = (1/L)(dL/dT), with units of 1/K or equivalently μm/(m·K). Typical values are aluminium ≈ 23 ×10⁻⁶ /K, copper ≈ 17, structural steel ≈ 12, glass ≈ 9, concrete ≈ 10–12, titanium ≈ 8.6, and Invar ≈ 1.2 ×10⁻⁶ /K. Fused silica is about 0.5. α itself rises slowly with temperature and drops toward zero near absolute zero, so handbook values are quoted over a stated temperature range.

How does thermal expansion create stress?

If a member is heated but rigidly held so it cannot expand, the free thermal strain ε = α·ΔT is suppressed and appears instead as mechanical strain. The resulting thermal stress is σ = E·α·ΔT, where E is the Young's modulus. Notably this stress does not depend on length. For steel (E ≈ 200 GPa, α ≈ 12 ×10⁻⁶ /K) a 100 °C rise produces about 240 MPa of compression — enough to buckle rails or crack constrained castings. Cooling a restrained part instead produces tension of the same magnitude.

Why are expansion joints used in bridges and railways?

Expansion joints give a structure room to grow and shrink so that thermal strain is accommodated as free movement instead of being converted into thermal stress. A 100-metre steel bridge deck swings roughly 84 mm between a −20 °C winter night and a +50 °C summer surface, so finger joints, roller bearings, or elastomeric bearings absorb that motion. Continuous welded rail is a special case: it is pre-tensioned (stress-neutral) at a rail neutral temperature and clamped hard so it cannot buckle, replacing joints with restraint plus careful installation temperature.

How does a bimetallic strip work?

A bimetallic strip bonds two metals with very different expansion coefficients — for example brass (α ≈ 19 ×10⁻⁶ /K) laminated to Invar (α ≈ 1.2). When heated, the brass side wants to grow much more than the Invar side, but the bond forces them to share a length, so the strip curves toward the low-expansion metal. The tip deflection is proportional to (α_high − α_low)·ΔT·L²/t, so a long, thin strip amplifies a tiny differential strain into a large, usable motion. This drives mechanical thermostats, circuit breakers, and older oven and iron controls.

What is Invar and why is its expansion so low?

Invar is a nickel–iron alloy of about 36% nickel with an anomalously low coefficient of thermal expansion, roughly 1.2 ×10⁻⁶ /K near room temperature — about ten times lower than ordinary steel. The near-zero expansion comes from a magnetostriction effect: as temperature rises the normal lattice expansion is almost exactly cancelled by a magnetic-volume contraction. Invar is used in precision instruments, laser cavities, clock pendulums, shadow masks, and cryogenic LNG tanker membranes. Related alloys include Super-Invar (≈ 0.3 ×10⁻⁶ /K) and Kovar, whose α is matched to borosilicate glass for hermetic seals.