Representation Theory
The Adjoint Representation: A Lie Algebra Acting on Itself
Every Lie algebra carries a canonical representation on itself β no auxiliary vector space required β and this single construction encodes the group's curvature, its Killing form, its root decomposition, and the entire classification of simple Lie algebras. The adjoint representation ad: π€ β π€π©(π€) sends each element X to the linear map ad_X(Y) = [X, Y], turning the bracket into a homomorphism whose Jacobi identity is nothing but the statement that ad is a Lie algebra representation.
At the group level, Ad: G β GL(π€) is conjugation acting on the tangent space at the identity, Ad_g = d(c_g)_e where c_g(h) = g h gβ»ΒΉ, and its differential at the identity recovers ad. This is the bridge on which the exponential map, the BakerβCampbellβHausdorff formula, and the structure theory of semisimple groups all rest.
- FieldLie theory / representation theory
- Definitionad_X(Y) = [X, Y], a map π€ β π€π©(π€)
- Group versionAd_g = d(c_g)_e, conjugation on π€ = T_e G
- Key identityJacobi βΊ ad is a Lie algebra homomorphism
- Named afterSophus Lie (1870s); Killing, Cartan (1888β1894)
- Kernelker(ad) = center π·(π€); ker(Ad) = Z(G)
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Precise statement: two maps and one differential
Let π€ be a Lie algebra over a field k with bracket [Β·,Β·]. The adjoint representation is the linear map ad: π€ β π€π©(π€) = End(π€), X β¦ ad_X, where ad_X(Y) = [X, Y]. The claim is that ad is a homomorphism of Lie algebras: ad_[X,Y] = [ad_X, ad_Y] = ad_X ad_Y β ad_Y ad_X, where the bracket on the right is the commutator of endomorphisms.
For a Lie group G with Lie algebra π€ β T_e G, define c_g(h) = g h gβ»ΒΉ (inner automorphism) and set Ad_g = d(c_g)_e β GL(π€). Then Ad: G β GL(π€) is a smooth group homomorphism (a representation on π€), and its differential at the identity is exactly ad: d(Ad)_e = ad. Equivalently, for all X β π€ one has the fundamental relation Ad(exp X) = exp(ad_X), an equality of operators on π€. For a matrix Lie group these specialize to Ad_g(Y) = gYgβ»ΒΉ and ad_X(Y) = XY β YX.
The picture: conjugation seen from the tangent space
The intuition is conjugation, linearized. The map c_g measures how far G is from abelian: if G were commutative, c_g would be the identity for every g. Ad_g captures the infinitesimal distortion conjugation induces on tangent vectors at e. So Ad packages the entire family of inner automorphisms into a single linear action on the fixed vector space π€.
Differentiating once more in g gives ad. Concretely, ad_X is the infinitesimal generator of the flow Y β¦ Ad(exp(tX))Y, so d/dt|β Ad(exp tX)Y = [X, Y]. Thus ad_X is the Lie derivative of the vector field along the one-parameter subgroup exp(tX): the bracket [X,Y] is exactly the failure of the flows of X and Y to commute, to first order. The adjoint representation is therefore the algebraic shadow of curvature β it is how the group 'twists' its own tangent directions into one another.
Key idea: the Jacobi identity IS a representation
The proof that ad is a homomorphism is the Jacobi identity in disguise, and this is the mechanism worth internalizing. We must show ad_[X,Y] = ad_X ad_Y β ad_Y ad_X. Apply both sides to an arbitrary Z:
Left side: ad_[X,Y](Z) = [[X,Y], Z].
Right side: ad_X ad_Y(Z) β ad_Y ad_X(Z) = [X,[Y,Z]] β [Y,[X,Z]].
These agree precisely when [[X,Y],Z] = [X,[Y,Z]] β [Y,[X,Z]], which, rearranged using antisymmetry, is the Jacobi identity [X,[Y,Z]] + [Y,[Z,X]] + [Z,[X,Y]] = 0. So ad being a representation is logically equivalent to Jacobi β no computation beyond bookkeeping is needed.
For the group side, Ad_g Ad_h = d(c_g)_e d(c_h)_e = d(c_g β c_h)_e = d(c_{gh})_e = Ad_{gh} by the chain rule and c_g β c_h = c_{gh}. Differentiating the identity Ad(exp X) = exp(ad_X) at X = 0 in the direction X recovers d(Ad)_e = ad.
Worked example: π°π²(2) and π°π¬(3)
Take π€ = π°π²(2) with basis Xβ, Xβ, Xβ satisfying [Xα΅’, Xβ±Ό] = Ξ΅_{ijk} Xβ (the structure constants are the Levi-Civita symbol). Compute ad_{Xβ} in this basis: ad_{Xβ}(Xβ) = [Xβ,Xβ] = Xβ and ad_{Xβ}(Xβ) = [Xβ,Xβ] = βXβ, while ad_{Xβ}(Xβ)=0. So the matrix of ad_{Xβ} is the 3Γ3 generator of rotations about the first axis β the adjoint representation of π°π²(2) is π°π¬(3) acting on βΒ³.
Exponentiating, Ad(exp(ΞΈXβ)) = exp(ΞΈ ad_{Xβ}) is rotation by ΞΈ about the Xβ-axis. This is the concrete face of the famous 2-to-1 cover SU(2) β SO(3): the group Ad(SU(2)) = SO(3), and the kernel of Ad is the center {Β±I}. The adjoint map literally exhibits SO(3) as SU(2) modulo its center, and shows why a 720Β° rotation in SU(2) descends to a 360Β° rotation in SO(3).
Where hypotheses bite: center, semisimplicity, and the Killing form
Faithfulness of ad requires a trivial center: ker(ad) = π·(π€) = {X : [X,Y]=0 βY}. For abelian π€ (e.g. ββΏ with zero bracket) ad β‘ 0, so the adjoint representation is useless β it forgets everything. Thus 'a Lie algebra acting on itself' is informative exactly to the extent that π€ is non-abelian. At the group level ker(Ad) = Z(G), the full center, for connected G (the differential statement ker(ad) = π·(π€) = Lie(Z(G)) only sees the identity component Z(G)Β°, but Ad itself kills the whole center, including its finite part), so Ad detects G only up to its center.
The payoff appears under semisimplicity. Cartan's criterion: π€ is semisimple iff the Killing form ΞΊ(X,Y) = tr(ad_X ad_Y) is non-degenerate. Here the invariance ΞΊ(ad_Z X, Y) + ΞΊ(X, ad_Z Y) = 0 (ad-invariance) is what makes ΞΊ a genuine tool. Drop semisimplicity and ΞΊ degenerates β its radical is a solvable ideal β and root-space theory collapses. Connections: the whole CartanβKilling classification, compactness (ΞΊ negative-definite βΊ compact semisimple), and Whitehead's lemmas / Lie algebra cohomology all hinge on this form built from ad.
Why it matters: roots, curvature, and BCH
The adjoint representation is the engine of semisimple structure theory. Fix a Cartan subalgebra π₯ β π€; the operators {ad_H : H β π₯} commute and are simultaneously diagonalizable, giving the root space decomposition π€ = π₯ β β¨_{Ξ±βΞ¦} π€_Ξ±, where π€_Ξ± = {X : ad_H X = Ξ±(H)X βH}. The roots Ξ± are eigenvalues of the adjoint action; the entire AβDβE classification of simple Lie algebras is read off from how these root vectors bracket, i.e. from ad restricted to root spaces.
Beyond classification, Ad(exp X) = exp(ad_X) is the algebraic core of the BakerβCampbellβHausdorff formula exp X exp Y = exp(X + Y + Β½[X,Y] + β¦), whose higher terms are iterated ad's. In differential geometry, ad governs the curvature of bi-invariant metrics (R(X,Y)Z = βΒΌ[[X,Y],Z]) and the holonomy of principal bundles. In physics it is the gauge field's transformation law: the field strength lives in the adjoint. It is, in short, the representation you cannot avoid.
| Feature | ad: π€ β π€π©(π€) | Ad: G β GL(π€) |
|---|---|---|
| Formula | ad_X(Y) = [X, Y] | Ad_g(Y) = d(c_g)_e(Y), c_g(h)=ghgβ»ΒΉ |
| For matrix groups | ad_X(Y) = XY β YX | Ad_g(Y) = g Y gβ»ΒΉ |
| Kernel | center π·(π€) = {X : [X,Β·]=0} | Z(G) for connected G; the full center |
| Linking identity | d(Ad)_e = ad | Ad(exp X) = exp(ad_X) |
| Invariant form | Killing ΞΊ(X,Y)=tr(ad_X ad_Y) | ΞΊ(Ad_g X, Ad_g Y) = ΞΊ(X,Y) |
| Faithful when | π€ has trivial center | G connected, semisimple, centerless |
Frequently asked questions
Why is ad automatically a Lie algebra homomorphism?
Because the requirement ad_[X,Y] = [ad_X, ad_Y] is exactly the Jacobi identity. Applying both sides to a vector Z and expanding via the bracket, the equation [[X,Y],Z] = [X,[Y,Z]] β [Y,[X,Z]] is Jacobi rearranged using antisymmetry. So no extra hypothesis is needed: any Lie algebra satisfies Jacobi by definition, hence ad is always a representation.
When is the adjoint representation faithful?
ad is faithful iff its kernel, the center π·(π€) = {X : [X,Y]=0 for all Y}, is zero. Semisimple Lie algebras have trivial center, so for them ad is faithful and embeds π€ βͺ π€π©(π€) β this is one proof that every semisimple Lie algebra is linear. For abelian π€, ad β‘ 0, the opposite extreme.
How exactly do ad and Ad relate?
Ad is the group representation g β¦ d(c_g)_e coming from conjugation, and ad is its differential at the identity: d(Ad)_e = ad. The two are tied by Ad(exp X) = exp(ad_X), an equality of operators on π€. Differentiating Ad(exp tX) at t = 0 gives ad_X, and this is how the group-level twisting linearizes to the bracket [X,Β·].
What is the Killing form and why build it from ad?
ΞΊ(X,Y) = tr(ad_X ad_Y) is a symmetric bilinear form intrinsic to π€, requiring no chosen representation β only the bracket. It is ad-invariant: ΞΊ([Z,X],Y) + ΞΊ(X,[Z,Y]) = 0. Cartan's criterion says π€ is semisimple iff ΞΊ is non-degenerate, and ΞΊ is negative-definite iff π€ is the Lie algebra of a compact semisimple group. So ΞΊ diagnoses the deepest structural facts using only ad.
Does the adjoint representation see the whole group?
No β Ad only detects G up to its center. For connected G, ker(Ad) = Z(G) (the full center), so Ad(G) β G/Z(G), the adjoint group. The example SU(2) β SO(3) has kernel {Β±I}: the adjoint representation collapses the two-element center, which is why SO(3) is the 'centerless' or adjoint form of the SU(2)-type group.
How does ad produce the roots of a semisimple Lie algebra?
Pick a Cartan subalgebra π₯ (a maximal abelian subalgebra of semisimple elements). The commuting operators ad_H, H β π₯, are simultaneously diagonalizable, decomposing π€ into eigenspaces π€_Ξ± where ad_H acts by the scalar Ξ±(H). The nonzero eigenfunctionals Ξ± β π₯* are the roots, and the combinatorics of how root vectors bracket under ad is precisely the root system that classifies π€.