Mechanics

Escape Velocity

The minimum speed to leave a body's gravity forever — v = √(2GM/r)

Escape velocity is the minimum speed needed to permanently leave a gravitational body without further propulsion — v_escape = √(2GM/r). On Earth's surface, it's 11.2 km/s. On the Moon, 2.4 km/s. From a black hole's event horizon, exactly the speed of light. Critical for spaceflight design — every interplanetary mission must achieve at least Earth's escape velocity. Connected to gravitational potential energy via energy conservation.

  • Formulav_escape = √(2·G·M / r)
  • Earth surface11.2 km/s
  • Moon surface2.4 km/s
  • Sun surface617 km/s
  • From event horizon of black holec (speed of light, by definition)
  • Compared to circular orbitv_escape = √2 · v_orbit at same r

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The formula

To escape gravity from a body of mass M at distance r:

v_escape = √(2 · G · M / r)

where G = 6.674 × 10⁻¹¹ N·m²/kg² is the gravitational constant.

This is the minimum speed needed; any higher and the object also escapes (with leftover speed at infinity). Lower, and it doesn't escape — falls back or settles into an elliptical orbit.

Derivation

Energy conservation. At launch (radius r), assume velocity v:

E_initial = KE + PE = ½·m·v² + (-GMm/r)

At infinity (the boundary of escape), the object should have at least zero kinetic energy and zero PE (PE → 0 as r → ∞):

E_final ≥ 0

For the borderline case (just barely escaping):

½·m·v² + (-GMm/r) = 0
v² = 2GM/r
v = √(2GM/r)

Escape velocities of common bodies

Bodyv_escapeFrom surface or relative to body
Earth (surface)11.2 km/sFrom R_E ≈ 6,371 km
Moon (surface)2.4 km/sFrom R_m ≈ 1,737 km
Mars (surface)5.0 km/sFrom R_Mars ≈ 3,390 km
Mercury (surface)4.3 km/s
Jupiter (cloud tops)59.5 km/s
Saturn (cloud tops)35.5 km/s
Sun (surface)617 km/sFrom solar radius
Solar system (from Earth's orbit)42.1 km/sTo leave the Sun's gravity
Milky Way (from Sun's location)~550 km/sTo escape the galaxy
Black hole event horizonc (≈ 3 × 10⁸ m/s)By definition of horizon

Escape velocity vs orbital velocity

For a circular orbit at radius r — v_orbit = √(GM/r). For escape — v_escape = √(2GM/r). So:

v_escape = √2 · v_orbit ≈ 1.414 · v_orbit

For Earth at surface: v_orbit = 7.9 km/s (would skim Earth's surface), v_escape = 11.2 km/s.

From low Earth orbit (~400 km up): v_orbit = 7.7 km/s, v_escape = 10.9 km/s.

SpeedTrajectory
v < v_orbitFalls back (parabolic to surface, or sub-orbital)
v = v_orbitCircular orbit
v_orbit < v < v_escapeElliptical orbit
v = v_escapeParabolic trajectory (just barely escapes)
v > v_escapeHyperbolic trajectory (escape with leftover energy)

Black holes — when v_escape = c

For a body of mass M, the radius at which escape velocity equals the speed of light:

c² = 2GM/r_s
r_s = 2GM/c²

This is the Schwarzschild radius. Any object compressed within this radius forms a black hole — no escape, even for light.

ObjectMassSchwarzschild radius
Earth5.97 × 10²⁴ kg8.9 mm (less than a marble!)
Sun1.99 × 10³⁰ kg2.95 km
Stellar black hole (10 M_sun)1.99 × 10³¹ kg30 km
Supermassive (Sagittarius A*)4.3 × 10⁶ M_sun~13 million km (~0.09 AU)

JavaScript — escape velocity calculations

const G = 6.674e-11;

function escapeVelocity(M, r) {
  return Math.sqrt(2 * G * M / r);
}

function orbitalVelocity(M, r) {
  return Math.sqrt(G * M / r);
}

// Earth surface
const M_EARTH = 5.972e24;
const R_EARTH = 6.371e6;
console.log(`Earth escape: ${(escapeVelocity(M_EARTH, R_EARTH)/1000).toFixed(2)} km/s`); // 11.18
console.log(`Earth orbit: ${(orbitalVelocity(M_EARTH, R_EARTH)/1000).toFixed(2)} km/s`); // 7.91
console.log(`Ratio: ${escapeVelocity(M_EARTH, R_EARTH) / orbitalVelocity(M_EARTH, R_EARTH)}`); // √2

// Moon
const M_MOON = 7.342e22;
const R_MOON = 1.737e6;
console.log(`Moon escape: ${(escapeVelocity(M_MOON, R_MOON)/1000).toFixed(2)} km/s`); // 2.38

// From low Earth orbit altitude
console.log(`Escape from LEO 400km: ${(escapeVelocity(M_EARTH, R_EARTH + 400e3)/1000).toFixed(2)} km/s`);

// Schwarzschild radius
const c = 3e8;
function schwarzschildRadius(M) {
  return 2 * G * M / (c * c);
}

const M_SUN = 1.989e30;
console.log(`Sun's r_s: ${(schwarzschildRadius(M_SUN)).toFixed(0)} m`);  // ~2950 m
console.log(`Earth's r_s: ${(schwarzschildRadius(M_EARTH)*1000).toFixed(2)} mm`);  // ~8.9 mm

// Tsiolkovsky rocket equation: how much fuel to escape Earth?
function rocketDeltaV(massInitial, massFinal, vExhaust) {
  return vExhaust * Math.log(massInitial / massFinal);
}

// Required Δv = ~11.2 km/s; chemical rocket v_e ~ 4500 m/s
const vEsc = escapeVelocity(M_EARTH, R_EARTH);
const massRatio = Math.exp(vEsc / 4500);
console.log(`Mass ratio for chemical rocket to escape Earth: ${massRatio.toFixed(2)}`); // ~12.3
console.log(`That means ${((1 - 1/massRatio) * 100).toFixed(1)}% must be fuel`);  // ~92%

Where escape velocity matters

  • Spaceflight. Every interplanetary or interstellar mission must overcome local escape velocity. Apollo, Voyager, New Horizons all achieved Earth escape (~11 km/s) plus more.
  • Astrophysics. Atmospheric retention — Earth retains heavy gases (N₂, O₂) at thermal speeds well below escape; loses light gases (H, He) over time. Mars lost most of its atmosphere because gravity is weaker.
  • Black hole physics. Schwarzschild radius defines event horizons. Beyond it, no escape.
  • Cosmology. Universe expansion vs gravitational binding — galaxies near each other are gravitationally bound; distant ones receding faster than escape velocity due to dark energy.
  • Planetary defense. Asteroid deflection — if you give an asteroid enough Δv to exceed Earth's gravitational pull, it doesn't return.
  • Engineering rockets. Multi-stage designs minimize fuel mass; orbital velocity (~7.7 km/s) is "halfway" to escape (~11.2 km/s) in terms of energy.
  • Educational physics. Beautiful application of energy conservation — derives a complex result from a simple energy budget.

Common mistakes

  • Confusing escape velocity with orbital velocity. Orbital v is to circle; escape v is to leave forever. Escape is √2 × orbital.
  • Thinking escape velocity is "the speed needed to fly forever." It's the minimum starting speed to escape WITHOUT further propulsion. With continuous thrust, you can escape at any speed (just takes longer).
  • Treating it as a "max speed." Escape velocity is a launch speed. Once moving, the object slows as it climbs (gravity pulls it back). At infinity, ideally zero kinetic energy left.
  • Ignoring height of launch. v_escape decreases with altitude (smaller GM/r). Launching from a high mountain or LEO requires less escape velocity than from sea level.
  • Forgetting the radius is from CENTER, not surface. v_escape = √(2GM/r) where r is distance from central body's center, not "altitude above surface." For Earth surface, r = R_Earth ≈ 6,371 km.
  • Using Newton's formula for high gravity. Near black holes, general relativity changes things. Newton's escape velocity formula is good for low-gravity regimes but breaks down at extreme gravity.

Frequently asked questions

Why is the formula √(2GM/r)?

Energy conservation. At surface — KE = ½mv² and gravitational PE = -GMm/r. To escape (reach infinity with v = 0), final KE = 0 and final PE = 0. Setting initial total = final total — ½mv² + (-GMm/r) = 0 → v = √(2GM/r). The "2" comes from the kinetic-energy formula's ½ canceling with the potential's negation.

Why does the formula not depend on the escaping object's mass?

Mass cancels in the energy equation. Both KE (½mv²) and PE (GMm/r) scale with m linearly, so they cancel. This means a 1 kg rock and a 1000 kg spacecraft need the SAME escape velocity from a given location (though the rocket needs more total energy because it has more mass).

How does escape velocity compare to orbital velocity?

At same distance r — v_escape = √2 · v_orbit ≈ 1.414 · v_orbit. So if you double-orbit speed, you'll escape (just barely). Going just slightly above orbital — you'll go on an elliptical orbit; achieving exactly v_escape — parabolic trajectory (just barely escapes); above — hyperbolic trajectory (lots of energy left over).

Why is Earth's escape velocity 11.2 km/s but rockets cruise at 7-8 km/s for orbit?

7-8 km/s is the orbital velocity at low Earth orbit (LEO) — enough to orbit, not escape. From LEO altitude (~400 km up), escape velocity is ~10.9 km/s (slightly less than 11.2 from surface, because already higher). To escape from surface, you need to reach 11.2 km/s relative to Earth's center. Real launches involve multiple stages and trajectory optimization.

What happens at exactly escape velocity?

The object follows a parabolic trajectory — barely escapes, asymptotically approaching zero velocity at infinity. Above escape velocity, hyperbolic trajectory with positive kinetic energy at infinity. Below, elliptical orbit (returns). Escape velocity is the boundary between bound and unbound trajectories.

How is escape velocity related to black holes?

A black hole's event horizon is defined as the radius where escape velocity equals c (speed of light). Setting v = c → r_s = 2GM/c² (Schwarzschild radius). Inside this radius, NOTHING (not even light) can escape. For Earth's mass, r_s = 8.9 mm; for the Sun, 3 km; for typical stellar-mass black holes, 30 km. Physical black holes form when stars collapse to within their Schwarzschild radius.

Why do rockets use multi-stage designs to escape Earth?

Tsiolkovsky rocket equation: Δv = v_e · ln(m_initial/m_final). To reach 11.2 km/s with chemical rockets (v_e ~ 4500 m/s), need m_initial/m_final = e^(11200/4500) ≈ 12.3. So 92% of the rocket must be fuel. Multi-stage designs drop empty fuel tanks to improve mass ratio. Single-stage-to-orbit (SSTO) is theoretically possible but mass-ratio-marginal; current designs use 2-3 stages.