Mechanics
Newton's Third Law
For every action there's an equal and opposite reaction — forces always come in pairs
Newton's third law states that for every action force, there is an equal and opposite reaction force. Forces always come in pairs that act on different objects. When you push a wall, the wall pushes back with the same force. This is why rockets work (exhaust gas pushes spacecraft forward), why guns recoil, and why you can walk (your foot pushes the ground backward, the ground pushes you forward).
- StatementF_AB = −F_BA — forces come in equal-opposite pairs
- Key insightThe pair acts on DIFFERENT objects
- Why we walkFoot pushes ground back; ground pushes you forward
- Why rockets workExhaust pushed back; rocket pushed forward
- Conserves momentumAlways — no isolated force exists
- First statedNewton's Principia, 1687
Interactive visualization
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Watch the 60-second explainer
A condensed visual walkthrough — narrated, captioned, under a minute.
The law
For every force, there is an equal and opposite force.
If object A exerts force F on object B, then object B simultaneously exerts force −F on object A. The forces are equal in magnitude and opposite in direction.
F_AB = −F_BA
The crucial point — these forces act on DIFFERENT objects. They don't cancel out (they're not on the same object).
Action-reaction pairs everywhere
| Action | Reaction | Result |
|---|---|---|
| Foot pushes ground backward | Ground pushes foot forward | You walk forward |
| Rocket pushes exhaust gas backward | Gas pushes rocket forward | Rocket accelerates |
| Bullet fired forward | Gun recoils backward | Recoil felt by shooter |
| Earth pulls apple down | Apple pulls Earth up | Both accelerate (Earth's tiny) |
| Tire pushes road backward | Road pushes tire forward | Car accelerates forward |
| Swimmer pushes water back | Water pushes swimmer forward | Swimmer moves forward |
| Helicopter blade pushes air down | Air pushes blade up | Helicopter rises |
| Hammer hits nail (force on nail) | Nail pushes hammer back | Hammer decelerates after impact |
Why action-reaction doesn't cancel motion
The most common confusion — "if forces are equal and opposite, why does anything move?"
Answer — they act on different objects. Each object has its own ΣF = ma equation:
- You push a heavy stalled car with force F. Car gets force F (forward), accelerates a tiny bit.
- By Newton's third, car pushes you back with force F (backward). YOU get force F backward.
- But you also have friction from your feet on the road, pushing you forward.
- Net force on you: friction − reaction = small or zero. You don't accelerate.
- Net force on car: only your push (no friction balancing). Car accelerates.
So both forces are real, equal in magnitude, but applied to different objects with different other forces.
Rockets and propulsion
The third law is the foundation of all propulsion:
| System | What's pushed back | What's pushed forward |
|---|---|---|
| Rocket | Exhaust gas (high velocity) | Rocket body |
| Jet engine | Air (accelerated through engine) | Aircraft |
| Propeller (boat/airplane) | Water/air (pushed back) | Vehicle |
| Walking | Ground (foot pushes it back) | Person (ground pushes back) |
| Swimming | Water (pushed by hands/feet) | Swimmer |
| Squid/octopus | Water (jetted out) | Squid (forward) |
Note — rockets work in vacuum (no air to push against) precisely because the law says the rocket and exhaust push on EACH OTHER. No external medium is needed.
Momentum conservation as a consequence
If forces always come in equal-opposite pairs, then internal forces in an isolated system can't change the system's total momentum. Here's why:
For any two objects A and B in a system, F_AB = −F_BA. Over time dt, A's momentum changes by F_AB·dt. B's changes by F_BA·dt = −F_AB·dt. Total change: F_AB·dt + (−F_AB·dt) = 0.
This holds for every pair, so the total momentum of an isolated system never changes. Momentum conservation is a direct consequence of Newton's third law.
JavaScript — collision via 3rd law
// Two-body interaction: equal-opposite forces, momentum conserved
class Body {
constructor(mass, x, vx) {
this.mass = mass;
this.x = x;
this.vx = vx;
}
}
// Apply equal-opposite forces over dt
function step(a, b, F_AB, dt) {
// Force on A from B is F_AB; force on B from A is -F_AB
a.vx += (F_AB / a.mass) * dt;
b.vx += (-F_AB / b.mass) * dt;
a.x += a.vx * dt;
b.x += b.vx * dt;
}
// Verify momentum conservation
function totalMomentum(bodies) {
return bodies.reduce((sum, b) => sum + b.mass * b.vx, 0);
}
const ball1 = new Body(2, 0, 5);
const ball2 = new Body(3, 5, -3);
console.log('Initial momentum:', totalMomentum([ball1, ball2])); // 2*5 + 3*(-3) = 1
// Apply 100 N from 2 onto 1 for 0.1 second (so 100 N from 1 onto 2 in reverse)
step(ball1, ball2, 100, 0.1);
console.log('After force pair:', totalMomentum([ball1, ball2])); // Still 1 ✓
// Rocket simulation: thrust = exhaust mass flow × velocity
function rocketStep(rocket, dt, exhaustMassRate, exhaustVelocity) {
// Force on rocket = +exhaustMassRate × exhaustVelocity (forward)
// Equal opposite on exhaust (we don't track exhaust here)
const thrust = exhaustMassRate * exhaustVelocity;
rocket.vx += (thrust / rocket.mass) * dt;
rocket.x += rocket.vx * dt;
rocket.mass -= exhaustMassRate * dt; // mass decreases
}
const rocket = new Body(1000, 0, 0);
for (let t = 0; t < 60; t++) {
rocketStep(rocket, 1, 10, 2500); // burn 10 kg/s, exhaust at 2500 m/s
}
console.log(`After 60s: v = ${rocket.vx.toFixed(0)} m/s, m = ${rocket.mass.toFixed(0)} kg`);
Identifying paired forces
Always ask — what's the action, and what's the reaction?
| Force | Paired with |
|---|---|
| Earth's gravity on you (your weight) | Your gravity on Earth (yes — you pull Earth!) |
| Floor's normal force on you | Your weight pressing down on floor |
| Air resistance on a falling skydiver | Skydiver pushing air down |
| Spring pulling on you | You pulling on spring |
| Magnet attracting iron | Iron attracting magnet (yes — both ways) |
| Sun's gravity on Earth | Earth's gravity on Sun (Earth slightly tugs Sun) |
Note — gravity on you from Earth is paired with YOUR gravity on Earth, NOT with the normal force from the floor. The normal force is a different action-reaction pair (you push down on floor; floor pushes up on you).
Where Newton's third law shows up
- Propulsion. Rockets, jets, propellers, walking, swimming, squid jets — all third-law applications.
- Recoil. Firearms, cannons, sneeze backward force, recoil from blocks of firework launching.
- Collision physics. All collisions involve action-reaction pairs; this is why momentum is conserved in collisions.
- Engineering — friction-based locomotion. Cars, trains, walking robots — all rely on friction (action-reaction with ground).
- Astrodynamics. Tidal forces (Earth pulls Moon, Moon pulls Earth), gravitational interactions in N-body systems.
- Sports — every sport. Pushing off the ground (running), pushing water (swimming), pushing air (cycling), pushing the ball (throwing).
- Detecting non-inertial frames. Real forces have third-law partners; fictitious forces (centrifugal, Coriolis) don't. If you can't find a partner, you might be in a non-inertial frame.
Common mistakes
- Thinking action-reaction pairs cancel. They act on DIFFERENT objects, so they don't cancel — each object analyzes its own ΣF separately.
- Pairing the wrong forces. Gravity on you (weight) pairs with YOUR gravity on Earth, not with normal force from floor. The normal force pair is your push on the floor.
- Forgetting that lighter objects accelerate more. Action-reaction forces are equal in MAGNITUDE, but accelerations are F/m. A bullet's acceleration is huge; the gun's is much smaller. Equal forces, very different accelerations.
- Ignoring third-law forces in dynamics. When the apple falls toward Earth, Earth also "falls" toward the apple — by an immeasurably tiny amount, but technically. For two-body problems (binary stars, Earth-Moon), this matters.
- Applying it to fictitious forces. Centrifugal and Coriolis don't have third-law partners. They appear in non-inertial frames as bookkeeping devices.
- Confusing 3rd law with equilibrium. 3rd law says forces come in pairs (always true). Equilibrium says ΣF = 0 on a single object (only true at rest or constant velocity). Different concepts.
Frequently asked questions
Why don't action-reaction pairs cancel out?
They act on DIFFERENT objects. When you push a wall (force on wall), the wall pushes you back (force on you) — these are equal and opposite, but acting on separate objects, so they don't cancel. The wall doesn't move (massive, fixed); you don't move (your feet are planted), but the FORCES are real and matter for individual analysis (e.g., how hard your hand presses, how the wall might crack).
How does this explain rocket propulsion?
A rocket expels gas backward at high velocity. The exhaust gas pushes the rocket FORWARD with equal and opposite force. No "ground" is needed — the rocket and exhaust gas push on each other. Momentum is conserved — total before launch is zero (everything at rest), after is rocket forward + exhaust backward (equal magnitudes, sum still zero). This is why rockets work in vacuum.
Why do guns recoil?
When the bullet is fired forward, the gun is pushed backward with equal force (action-reaction). Momentum conservation — bullet + gun has zero initial momentum; after firing, bullet goes forward with mv_bullet, gun recoils with -Mv_gun, where M is much larger so v_gun is much smaller. Kinetic energy isn't conserved (most goes into the bullet, some into recoil, sound, heat).
When you push a heavy box and it doesn't move, are the forces really equal?
Yes — your push and the box's reaction are equal and opposite. The box doesn't move because there are OTHER forces too — namely, friction between box and floor (and whatever wall behind it). The net force on the box is zero (ΣF = 0), so it doesn't accelerate (Newton's first law). But your push and the reaction are still equal magnitude.
Why does horse-and-cart "paradox" confuse students?
The paradox — horse pulls cart with force F; cart pulls horse back with force F (3rd law). If equal and opposite, why does the cart accelerate? Resolution — the action-reaction pair is between horse and cart; but the SYSTEM (horse + cart) accelerates because the GROUND pushes the horse forward (friction), and that's a separate force not paired with the cart-pulling-horse force. Always identify which forces are paired and which aren't.
How does this conserve momentum?
For every force-pair, both objects experience equal-magnitude impulses (F·dt) in opposite directions. Their changes in momentum are equal and opposite, so their TOTAL momentum stays constant. This is why momentum conservation in collisions is a direct consequence of Newton's third law. Internal forces in any system don't change the system's total momentum.
Does this work in non-inertial frames?
The third law is a real-force law — it says real forces come in pairs. Fictitious forces (centrifugal, Coriolis) in non-inertial frames do NOT have third-law partners. So in a rotating frame, you appear to feel an outward "centrifugal force" with no equal-opposite partner. This is one way to detect non-inertial frames.