Electromagnetism
Poynting Vector
S = E × H — how much electromagnetic energy is flowing where, in watts per square meter
The Poynting vector S = E × H is the energy-flux density of the electromagnetic field. Its magnitude is W/m², its direction is the way energy flows. Sunlight at Earth's surface ≈ 1000 W/m².
- DefinitionS = E × H = (1/μ₀)·E × B
- UnitsW/m² (watts per square meter)
- DirectionEnergy flow (right-hand rule)
- Closed-surface integral∮ S·dA = radiated power
- Sunlight at Earth surface≈ 1000 W/m² (solar constant 1361 W/m²)
- Sun's photosphere|S| ≈ 6.3 × 10⁷ W/m²
Interactive visualization
A plane EM wave: E in red, H in blue, S = E × H as a gold arrow pointing along propagation. The closed-surface integral picks out the radiated power.
Watch the 60-second explainer
A condensed visual walkthrough — narrated, captioned, under a minute.
Definition
The Poynting vector in SI units is:
S = E × H = (1/μ₀)·E × B [W/m²]
It is a flux density — the rate of energy transport per unit area perpendicular to S. Direction follows the right-hand rule applied to E and H.
In Gaussian units S = (c/4π)·E × B; the dimensions still come out as energy/area/time.
Poynting's theorem
Start from Maxwell's equations. Multiply Faraday's law by H, Ampère's law by E, subtract, and rearrange. You get:
∂u/∂t + ∇·S = −J·E
u = ½·(ε₀·E² + B²/μ₀) [energy density of the EM field, J/m³]
S = E × H [energy flux density, W/m²]
J·E [power per unit volume done by fields on charges]
Integrate over a volume V bounded by surface ∂V:
d/dt ∫_V u dV + ∮_{∂V} S · dA = −∫_V J·E dV
Translation: rate of change of EM energy inside + power flowing out through the boundary = power dissipated into matter inside. Energy conservation, expressed entirely in field language.
Plane wave example
Consider a linearly polarized plane wave traveling in +z, with E pointing along x and B along y:
E(z, t) = E₀·cos(kz − ωt)·x̂
B(z, t) = (E₀/c)·cos(kz − ωt)·ŷ
S = E × H = (E₀²/(μ₀·c))·cos²(kz − ωt)·ẑ
Time average:
⟨S⟩ = (E₀²)/(2·μ₀·c) = (½)·ε₀·c·E₀² = ½·c·ε₀·E₀² [W/m²]
The time-averaged intensity is half the peak — same factor of ½ you see in AC power. In a non-magnetic medium with refractive index n, replace c with c/n and add factor n.
Real-world magnitudes
| Source | |⟨S⟩| | Peak E-field |
|---|---|---|
| Solar constant (top of atmosphere) | 1361 W/m² | ~1000 V/m |
| Sunlight at Earth's surface (clear noon) | ≈ 1000 W/m² | ~870 V/m |
| Sun's photosphere (Stefan-Boltzmann at 5778 K) | 6.32 × 10⁷ W/m² | ~2.2 × 10⁵ V/m |
| Microwave oven interior | ~10⁴ W/m² | ~2700 V/m |
| Smartphone WiFi (1 m away) | ~10⁻⁴ W/m² | ~0.3 V/m |
| FM radio at 10 km from 50 kW transmitter | ~4 × 10⁻⁶ W/m² | ~0.05 V/m |
| Cell-phone-tower exposure limit (FCC) | 10 W/m² at 1900 MHz | ~87 V/m |
| CMB background | 3.13 × 10⁻⁶ W/m² | tiny |
| Pulsed laser (1 mJ, 100 fs, 100 μm² spot) | ~10¹⁸ W/m² | ~10⁹ V/m |
Numerical sanity check: ⟨S⟩ = 1000 W/m² ⟹ E₀ = √(2·μ₀·c·⟨S⟩) = √(2 · 4π·10⁻⁷ · 3×10⁸ · 1000) ≈ 870 V/m. So peak sunlight E-field at Earth's surface is roughly 1 kV per meter — surprising once you see it written down.
Worked example — radiated power from a dipole antenna
A short electric dipole of length L driven at angular frequency ω with current I₀ radiates in a doughnut pattern. The far-field Poynting magnitude on the equatorial plane at distance r is:
⟨|S|⟩ = (μ₀·ω²·I₀²·L²)/(32·π²·c·r²) · sin²θ
Total radiated power (integrate over the sphere):
P_rad = (μ₀·ω²·I₀²·L²)/(12·π·c) = ⅔ · (μ₀·c/12π) · (ω·I₀·L/c)²
For a 1 m dipole carrying 1 A at 100 MHz (ω = 6.28 × 10⁸ rad/s):
P_rad ≈ (4π·10⁻⁷ · (6.28×10⁸)² · 1² · 1²) / (12π·3×10⁸)
≈ 4.4 W
At r = 100 m, equatorial Poynting:
⟨|S|⟩ ≈ 4.4 / (4π · 100²) ≈ 3.5 × 10⁻⁵ W/m²
That is roughly the same magnitude as cellphone-tower exposure at moderate range, illustrating why exposure-limit calculations are essentially Poynting-vector accounting.
Radiation pressure
The momentum density carried by the EM field is g = S/c². A wave absorbed by a perfectly black surface exerts pressure P_rad = ⟨|S|⟩/c; a perfect reflector doubles it (2⟨|S|⟩/c). For sunlight at Earth (1361 W/m²):
P_rad(absorbed) = 1361 / (3 × 10⁸) ≈ 4.5 × 10⁻⁶ Pa
P_rad(reflected) ≈ 9 × 10⁻⁶ Pa
Tiny — but enough to accelerate solar-sail spacecraft like LightSail-2 over months, and to alter the orbits of small asteroids (Yarkovsky and YORP effects).
JavaScript — Poynting-vector arithmetic
const mu0 = 4 * Math.PI * 1e-7; // T·m/A
const eps0 = 8.854e-12; // F/m
const c = 2.998e8; // m/s
// Time-averaged Poynting magnitude for a plane wave
function S_avg(E0) { return (E0 * E0) / (2 * mu0 * c); }
// Peak E-field from time-averaged intensity
function E_from_S(S) { return Math.sqrt(2 * mu0 * c * S); }
console.log(`Solar S ≈ 1361 W/m² → E ≈ ${E_from_S(1361).toFixed(0)} V/m`); // ~1011
// Radiation pressure
function radiationPressure(S, mode = 'absorb') {
return mode === 'reflect' ? 2 * S / c : S / c;
}
console.log(`Solar sail pressure (reflect): ${radiationPressure(1361, 'reflect').toExponential(2)} Pa`);
// Total radiated power from short dipole
function dipoleRadiatedPower(I0, L, freq) {
const omega = 2 * Math.PI * freq;
return (mu0 * omega * omega * I0 * I0 * L * L) / (12 * Math.PI * c);
}
console.log(`1 A, 1 m, 100 MHz dipole: P_rad ≈ ${dipoleRadiatedPower(1, 1, 1e8).toFixed(1)} W`);
// Equatorial far-field Poynting at distance r
function dipoleS_equatorial(I0, L, freq, r) {
const omega = 2 * Math.PI * freq;
return (mu0 * omega * omega * I0 * I0 * L * L) / (32 * Math.PI * Math.PI * c * r * r);
}
console.log(`Dipole at 100 m: ${dipoleS_equatorial(1, 1, 1e8, 100).toExponential(2)} W/m²`);
// Solar irradiance per area of panel
function panelPower(area_m2, eff = 0.20, intensity = 1000) {
return area_m2 * intensity * eff;
}
console.log(`2 m² panel at 1000 W/m², 20%: ${panelPower(2, 0.20, 1000)} W`); // 400 W
// Stefan-Boltzmann surface flux for blackbody at T
function blackbodyFlux(T) {
const sigma = 5.670e-8;
return sigma * Math.pow(T, 4);
}
console.log(`Sun surface flux at 5778 K: ${blackbodyFlux(5778).toExponential(2)} W/m²`); // ~6.3e7
Where the Poynting vector shows up
- Antenna engineering. Directivity, gain, beam pattern, effective aperture — all defined via the angular distribution of ⟨|S|⟩ in the far field.
- Solar power and photovoltaics. Module rating is W per m² × area × efficiency. The 1361 W/m² solar constant is a Poynting magnitude.
- Optics. Light intensity, Beer-Lambert absorption, refractive-index interfaces — all written in terms of S. Reflection and transmission coefficients are ratios of Poynting fluxes.
- Transformer and motor design. Real magnetic-circuit engineers use Poynting flux to track where the power physically flows; counter-intuitively, transformer power flows through the air gap, not the iron.
- RF safety and exposure. FCC, ICNIRP, and other regulators specify maximum permissible exposure in W/m² (or equivalent V/m) — direct Poynting-vector limits.
- Wireless power transfer. Inductive charging, beamed microwave power (Apple/Qi, future space-based solar). Efficiency is measured as Poynting flux delivered vs. transmitted.
- Astrophysics. Stellar luminosities (W), pulsar spin-down power, jet kinetic luminosity — all integrated Poynting fluxes over the stellar surface or magnetosphere.
- Solar sails and radiation pressure. Momentum carried by the EM field equals S/c²; that's the underlying mechanism of every photon-pushed spacecraft.
Common mistakes
- Confusing E × H with E × B. In SI units S = E × H = (1/μ₀)·E × B. The factor of μ₀ matters: using E × B without dividing gives the wrong units and a 10⁷-fold error.
- Forgetting the time average. Instantaneous |E × H| oscillates at 2ω; for power calculations you want ⟨|S|⟩ = (1/2)·|E₀ × H₀|. Skipping the factor of ½ doubles your answer.
- Thinking energy flows through wires in a DC circuit. S = E × H around a current-carrying wire points sideways from the surrounding space into the resistor — energy travels through the field, not through the metal. The metal just guides the field.
- Treating S as gauge-invariant in detail. Total radiated power (∮S·dA) is unambiguous, but the local definition allows adding curls of arbitrary fields without changing the conservation law. The standard choice S = E × H is canonical because it correctly tracks momentum too.
- Ignoring the medium. In materials with refractive index n, the EM energy moves at c/n, and the Poynting magnitude needs μ replaced by μ = μ₀μ_r. For non-magnetic dielectrics S ≈ n·ε₀·c·⟨E²⟩.
- Forgetting that S can point into a conductor. Even though the perfect conductor has no internal S, real conductors with finite skin depth absorb a thin sheet of Poynting flux — that's how ohmic heating gets accounted for in field language.
Frequently asked questions
What does the Poynting vector represent physically?
S = E × H (in SI units; in Gaussian units S = c·(E × B)/4π) is the energy flux density of the electromagnetic field. Its magnitude is the power per unit area crossing a surface perpendicular to S, measured in watts per square meter. Its direction tells you which way EM energy flows. Integrate over a closed surface and you get the total power flowing through that surface — which equals the rate of energy lost by sources inside, by Poynting's theorem.
Why does S = E × H point in the direction of propagation?
In a plane EM wave traveling in +z, E oscillates along x and B (or H) along y, in phase. The cross product E × H then points along +z — exactly the direction of energy propagation. The right-hand rule from your intro physics class is identical to the Poynting vector direction. If you reverse one field (a left-going wave), the cross product reverses too.
What is Poynting's theorem?
Energy conservation for the EM field. In differential form: ∂u/∂t + ∇·S = −J·E, where u = ½(ε₀E² + B²/μ₀) is the energy density and J·E is the rate of work done on charges. Integrated over a volume: rate of change of EM energy inside + power flowing out through the surface = power delivered to the matter inside. Same shape as continuity equations — divergence of a flux plus time-derivative of a density equals a source.
How big is the Poynting vector for sunlight at Earth?
About 1000 W/m² at the surface on a clear noon (the solar constant outside the atmosphere is 1361 W/m²; atmospheric absorption and scattering remove ~25%). That's the time-averaged ⟨|S|⟩. Multiply by your area to get power: a 1 m² solar panel sees ~1 kW of incoming radiation, and a 20%-efficient panel converts that to ~200 W of electrical output. The Poynting magnitude varies seasonally and by latitude — the photosphere of the Sun itself has |S| ≈ 6.3 × 10⁷ W/m² (Stefan-Boltzmann at 5778 K).
Why is there no S inside a perfect conductor?
Inside an ideal conductor E = 0 everywhere (charges rearrange to cancel any internal field), so S = E × H = 0. Energy doesn't propagate into a perfect conductor — it reflects. In a real conductor with finite resistivity, fields penetrate to a skin depth δ ≈ √(2/(σμω)) and S is nonzero inside that thin layer, where the wave's energy is dissipated as ohmic heat.
Does the Poynting vector apply to DC circuits?
Yes, surprisingly. In a DC circuit with a battery and a resistor, the Poynting vector points sideways from the wires into the resistor — the energy actually flows through the surrounding space, not through the copper. The wires guide the fields; the fields carry the power. This is counterintuitive but unambiguous: ∮ S · dA over a surface enclosing the resistor equals I·V·t as expected from circuit theory.
Does S have any gauge ambiguity?
The Poynting vector itself is gauge-invariant — it depends only on the physical fields E and H. But its definition as the energy flux is not unique: you can add the curl of any vector field to S without changing ∇·S, so the differential conservation law allows many equivalent local choices. The integral over a closed surface (total power radiated) is unambiguous, and S = E × H is the canonical choice that matches both linear and angular momentum conservation.