Atomic Physics
Stark Effect
Switch on an electric field and an atom's energy levels slide apart — the electric twin of the Zeeman effect
The Stark effect is the shifting and splitting of atomic energy levels in an electric field — linear (∝ E) for hydrogen, quadratic (∝ E²) otherwise.
- DiscoveredJohannes Stark, 1913 (Nobel 1919)
- Linear (hydrogen)ΔE ∝ E — first order
- Quadratic (most atoms)ΔE = −½ α E²
- Why hydrogen is special2s/2p parity degeneracy
- Rydberg polarizabilityα ∝ n⁷ — up to a billion×
- CounterpartElectric analog of the Zeeman effect
Interactive visualization
Press play, or step through manually. Watch the levels split as the field ramps up — drive it yourself before reading on.
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A condensed visual walkthrough — narrated, captioned, under a minute.
Definition
The Stark effect is the shifting and splitting of atomic energy levels — and therefore spectral lines — in an external electric field. Place an atom in a field and its levels no longer sit at their field-free energies: some climb, some drop, and degenerate levels fan out into a pattern that grows with the field.
The headline result is that the size of the shift depends on the field in one of two ways:
Linear (hydrogen): ΔE ∝ E (first-order)
Quadratic (most atoms): ΔE = −½ α E² (second-order)
Here E is the applied electric field and α is the atom's polarizability — how readily the field stretches its electron cloud into a dipole. The Stark effect is the electric counterpart of the Zeeman effect, which splits the same levels using a magnetic field instead.
How it works
An atom in a field E gains an interaction energy H' = −d·E, where d = −e·r is the electric dipole operator. Perturbation theory then asks: what does this extra energy do to each level?
First order — the linear Stark effect. The first-order shift is the expectation value ⟨ψ|H'|ψ⟩. Because H' is odd under spatial inversion (it flips sign when you flip r → −r), this expectation value is zero for any state of definite parity. A non-zero first-order shift therefore demands states of opposite parity that share the same energy — a parity degeneracy the field can mix. Hydrogen has exactly this: the 2s and 2p levels are degenerate, so the field blends them and the level splits linearly. The result is a permanent dipole that lines up with the field.
Second order — the quadratic Stark effect. Most atoms have no such degeneracy. There the first-order term vanishes and the leading effect is second order — the field induces a dipole, and that induced dipole interacts back with the field:
ΔE = −½ α E²
The minus sign means the polarizable atom is always pulled toward stronger field (it lowers its energy by polarizing) — the same reason a neutral object is attracted to a charged comb. The polarizability α is a sum over all other states, dominated by the nearest ones:
α = 2 Σ_(k≠0) |⟨k|d|0⟩|² / (E_k − E_0)
Closely spaced levels (small denominators) make α large — which is exactly what happens in highly excited atoms.
A worked example — hydrogen n = 2
Take hydrogen's n = 2 manifold (the 2s and 2p states) and switch on a field. Working in atomic units, the four states split into a symmetric fan. The linear shift for the n = 2 stretched state is:
ΔE = 3 · n · E (atomic units, for the extreme state)
= 3 · 2 · E = 6E
Convert to lab numbers. One atomic unit of field is 5.14 × 10¹¹ V/m, and one atomic unit of energy (a Hartree) is 27.2 eV. A modest lab field of 10⁶ V/m is therefore E ≈ 1.9 × 10⁻⁶ atomic units, giving a shift of about 6 × 1.9 × 10⁻⁶ ≈ 1.2 × 10⁻⁵ Hartree ≈ 3 × 10⁻⁴ eV. That is small but absolutely measurable — it is exactly the order of splitting Stark saw smeared across hydrogen's Balmer lines in 1913.
Now contrast the ground state, which has no degeneracy and shifts quadratically. Hydrogen's ground-state polarizability is α = 4.5 atomic units (about 0.67 cubic ångströms). At the same 10⁶ V/m field:
ΔE = −½ α E² = −½ · 4.5 · (1.9 × 10⁻⁶)²
≈ −8 × 10⁻¹² Hartree ≈ −2 × 10⁻¹⁰ eV
Six orders of magnitude smaller than the linear n = 2 shift, at the same field. That gulf — linear versus quadratic — is the whole story of the Stark effect in one comparison.
Variants and regimes
| Regime | Field dependence | When it applies | Set by |
|---|---|---|---|
| Linear (first-order) | ΔE ∝ E | Hydrogen & degenerate parity states | Permanent / mixed dipole |
| Quadratic (second-order) | ΔE = −½ α E² | Most atoms, non-degenerate levels | Polarizability α |
| Rydberg quadratic | ΔE = −½ α E², α ∝ n⁷ | Highly excited atoms (large n) | Enormous α |
| Strong-field mixing | Non-perturbative | Field comparable to internal field | Full diagonalization |
| Field ionization | Tunneling / barrier suppression | E > threshold ≈ 1/(16 n⁴) a.u. | Tilted potential |
| AC (dynamic) Stark | ∝ intensity / detuning | Oscillating (laser) field | Dynamic polarizability |
The same atom moves through several of these regimes as you turn up the field. A ground-state atom starts quadratic; a Rydberg atom is quadratic but with a colossal α; push harder and perturbation theory fails, levels cross and mix non-perturbatively; push harder still and the atom field-ionizes.
Why Rydberg atoms steal the show
The single most dramatic fact about the Stark effect is how it scales with excitation. Almost every length and energy scale of a Rydberg atom follows a power of the principal quantum number n: the orbit radius grows as n², the level spacing shrinks as 1/n³, and — combining those — the polarizability grows as:
α ∝ n⁷
Going from the ground state to n = 50 multiplies α by roughly 50⁷ ≈ 8 × 10¹¹ — close to a trillion-fold increase in sensitivity. A field of a few V/cm, completely invisible to a ground-state atom, produces large, cleanly resolved Stark maps in a Rydberg atom. This is why:
- Rydberg atoms are used as field sensors — they can measure electric fields and even microwave fields with extraordinary precision, because the shift is huge and the resonance is narrow.
- Neutral-atom quantum computers use Rydberg states — the very polarizability that makes them field-sensitive also makes two nearby Rydberg atoms interact strongly (the Rydberg blockade), the basis for two-qubit gates.
- Field ionization detects them state-selectively — because the ionization threshold ≈ 1/(16 n⁴) drops fast with n, ramping a field ionizes high-n states first, reading out which level the atom was in.
Applications
- Spectroscopy and plasma diagnostics. Stark broadening of hydrogen lines is a standard, calibration-free thermometer for plasma electron density — the local microfields from ions and electrons broaden the lines by an amount that depends on density.
- Atomic clocks. The DC and AC (blackbody) Stark shifts are among the largest systematic frequency errors in optical lattice clocks; they must be measured and subtracted to reach the 18th decimal place.
- Optical traps and tweezers. The AC Stark shift from a focused laser creates a potential well that holds neutral atoms — the foundation of optical lattices and single-atom tweezer arrays.
- Quantum control. Stark-shifting a transition with a controllable field tunes atoms in and out of resonance, used for addressing individual qubits and for Stark-switching spectroscopy.
- Quantum-confined Stark effect. In semiconductor quantum wells the same physics shifts excitonic absorption with applied voltage, the operating principle of high-speed electro-optic modulators in fiber telecom.
- Field metrology. Rydberg-atom electrometers turn the n⁷ polarizability into self-calibrated, SI-traceable measurements of RF electric fields.
Common pitfalls and misconceptions
- "The Stark effect is always linear." Only hydrogen (and accidentally degenerate parity states) shift linearly. For every other atom the leading effect is quadratic — the linear term is forbidden by parity. Reaching for ΔE ∝ E on a sodium or helium line is a classic error.
- "The shift goes up with the field." The quadratic shift is negative: ΔE = −½ α E². A polarizable atom lowers its energy in a field, which is why it is attracted to high-field regions — the whole basis of optical trapping.
- Confusing polarizability with permanent dipole. Atoms have no permanent electric dipole in a non-degenerate state (parity forbids it); the field induces one. The induced dipole p = αE is what produces the quadratic shift. The linear hydrogen case effectively behaves as if it had a permanent dipole only because the field mixes degenerate states.
- Treating it as a magnetic effect. The Stark effect is electric (couples to charge displacement); the Zeeman effect is magnetic (couples to magnetic moment). They split the same levels but through entirely different couplings, and only the Stark effect can be quadratic.
- Forgetting field ionization. Perturbation theory eventually breaks. Above E ≈ 1/(16 n⁴) atomic units the bound state is no longer bound — it tunnels out. Quoting a clean Stark shift in a field that already ionizes the atom is meaningless.
- Ignoring the n⁷ scaling. A "tiny" field can be a huge perturbation for a Rydberg atom. The same field that shifts the ground state by 10⁻¹⁰ eV can completely scramble an n = 50 manifold.
Derivation and scaling analysis
Start from the perturbation H' = eEz (field along z). Standard time-independent perturbation theory gives the energy correction as a series in the field:
E_n = E_n⁽⁰⁾ + ⟨n|H'|n⟩ + Σ_(k≠n) |⟨k|H'|n⟩|² / (E_n⁽⁰⁾ − E_k⁽⁰⁾) + ...
└── 1st order ──┘ └────────── 2nd order ──────────┘
(∝ E) (∝ E²)
First-order term. ⟨n|z|n⟩ vanishes for any parity eigenstate, so the linear term is zero unless degenerate opposite-parity states force you into degenerate perturbation theory. For hydrogen's n = 2, diagonalizing H' in the {2s, 2p₀} subspace yields eigenvalues ±3eEa₀ — the linear splitting, symmetric about the unshifted level.
Second-order term. When the first order vanishes, the surviving correction is the quadratic sum above. Pulling out the field gives ΔE = −½ α E² with α defined by the matrix elements and energy denominators. Two scaling facts fall straight out:
- Why hydrogen is the exception. Only the Coulomb 1/r potential produces the "accidental" ℓ-degeneracy that places 2s and 2p at the same energy. Any deviation from pure 1/r — which every multi-electron atom has — lifts that degeneracy and kills the linear term.
- Why α ∝ n⁷. The dipole matrix element scales as the orbit size, ⟨d⟩ ∝ n²; squared that is n⁴. The relevant energy denominator is the level spacing, ∝ 1/n³. Multiply: α ∝ n⁴ · n³ = n⁷. This single estimate explains the entire Rydberg sensitivity story.
Field ionization scaling. The total potential along the field is −1/r − Ez (atomic units). The downhill side develops a saddle point; setting the barrier height equal to the binding energy −1/(2n²) gives a threshold field E_ion ≈ 1/(16 n⁴). The fourth-power suppression is why a Rydberg atom that needs only a few V/cm to show a Stark map needs only a slightly larger field to ionize entirely — the perturbative and non-perturbative regimes sit close together at high n.
Frequently asked questions
What is the Stark effect?
The Stark effect is the shifting and splitting of atomic and molecular energy levels — and therefore their spectral lines — when the atom sits in an external electric field. Johannes Stark discovered it in hydrogen in 1913 and shared the 1919 Nobel Prize for it. It is the electric counterpart of the Zeeman effect, which does the same thing using a magnetic field instead.
Why is the Stark shift linear in hydrogen but quadratic in other atoms?
A linear shift, ΔE ∝ E, requires the atom to have a permanent dipole component along the field — equivalently, degenerate states of opposite parity that the field can mix at first order. Hydrogen has exactly this: its 2s and 2p levels are degenerate (the same energy), so the field mixes them and produces a first-order, linear splitting. Most other atoms have no such degeneracy, so first-order perturbation theory gives zero and the leading term is second order: ΔE = −½ α E², quadratic in the field, set by the atom's polarizability α.
How does the Stark effect compare to the Zeeman effect?
They are direct analogs. The Zeeman effect splits levels in a magnetic field B and couples to the magnetic dipole moment; the Stark effect splits levels in an electric field E and couples to the electric dipole moment. Both lift degeneracy and split spectral lines. A key difference: magnetic moments are permanent, so the Zeeman shift is always linear in B, whereas electric dipoles are usually induced, making the Stark shift quadratic in E for most atoms (linear only when parity degeneracy exists, as in hydrogen).
Why are Rydberg atoms so sensitive to electric fields?
The polarizability of a Rydberg atom scales as the seventh power of the principal quantum number, α ∝ n⁷. Because the quadratic Stark shift is ΔE = −½ α E², an atom excited to n ≈ 50 can be a billion times more polarizable than its ground state. Fields of just a few volts per centimetre — utterly negligible for a ground-state atom — produce huge, easily measured shifts. This is why Rydberg atoms are used as ultra-sensitive electric-field sensors and as the qubits in neutral-atom quantum computers.
Can the Stark effect ionize an atom?
Yes. A strong enough field tilts the atom's potential into a finite barrier through which the electron can tunnel — field ionization. The Coulomb potential plus the linear field potential, −eEx, form a downhill slope on one side; once the field is strong enough the bound electron escapes. The classical threshold field for a hydrogen-like state of principal quantum number n is roughly E_ion ≈ 1/(16 n⁴) in atomic units, which is why high-n Rydberg states ionize at remarkably weak fields and are used for state-selective detection.
What is the DC Stark shift versus the AC Stark shift?
The DC Stark effect uses a static electric field and is what Stark originally measured. The AC (or dynamic) Stark effect uses an oscillating field, typically from a laser; it shifts levels by an amount set by the field's intensity and detuning, and is responsible for the light shift, the Autler–Townes doublet, and optical-trap potentials. The AC Stark shift is the workhorse behind optical tweezers, optical lattices, and laser cooling traps.
How big is a typical Stark shift in a laboratory field?
For a ground-state atom the quadratic shift is tiny. Hydrogen's ground-state polarizability is about 0.67 cubic ångströms (4.5 atomic units), so a strong lab field of 10⁶ V/m shifts the level by only a few times 10⁻⁹ eV — sub-microvolt energies. In hydrogen's n = 2 manifold the linear shift is far larger: roughly 3·n·E in atomic units, giving splittings of order 10⁻⁴ eV at the same field, which is why Stark first saw the effect in hydrogen's Balmer lines.