Quantum Mechanics
The Path Integral Formulation
Quantum mechanics as a sum over all possible paths, each weighted by e^(iS/ℏ)
The path integral formulation is Richard Feynman's 1948 reformulation of quantum mechanics in which the amplitude for a particle to travel from point A to point B is a sum over every possible path connecting them, each path contributing a complex phase e^(iS/ℏ), where S = ∫L dt is the classical action and ℏ = 1.055 × 10⁻³⁴ J·s. Paths far from the classical trajectory interfere destructively (stationary phase), leaving the classical path — where δS = 0 — to dominate. It is mathematically equivalent to Schrödinger's and Heisenberg's pictures, reproduces the Schrödinger equation, reinterprets the double-slit experiment, and generalizes to the functional integrals that define quantum field theory.
- PropagatorK(b,a) = ∫ Dx e^(iS[x]/ℏ)
- Weight per pathe^(iS/ℏ), |amplitude| = 1
- ActionS = ∫ L dt, L = T − V
- Classical limitδS = 0 (stationary phase, ℏ → 0)
- ℏ (reduced Planck)1.055 × 10⁻³⁴ J·s
- Introduced byR. P. Feynman, 1948
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The core idea: add up every path
Classical mechanics answers "how does a ball get from A to B?" with a single trajectory — the one that extremizes the action. Quantum mechanics, in Feynman's telling, refuses to choose. To compute the amplitude to go from A to B, you consider every conceivable path: the straight one, the wiggly one, the one that loops back on itself, even the one that momentarily runs faster than light. Each path x(t) is assigned a complex number of unit magnitude,
amplitude of one path = e^(iS[x]/ℏ)
where S[x] is the classical action of that path. The total amplitude is the sum (an integral, really) of all these unit-length arrows in the complex plane:
K(b, a) = Σ_all paths e^(iS[x]/ℏ) → ∫ Dx(t) e^(iS[x]/ℏ)
The probability to arrive at B is |K(b, a)|². Every path contributes the same magnitude (1) — what differs is the phase. All of quantum interference is contained in how those phases add or cancel.
The propagator and its symbols
The central object is the propagator (or kernel) K, the amplitude to be found at (x_b, t_b) given a start at (x_a, t_a):
K(b, a) = ⟨x_b, t_b | x_a, t_a⟩ = ∫ Dx(t) exp( (i/ℏ) S[x(t)] )
| Symbol | Meaning | Units (SI) |
|---|---|---|
| K(b, a) | Propagator / kernel — amplitude from a to b | m⁻¹ (1D), so |K|² is a probability density |
| S[x(t)] | Action functional of a path, S = ∫ L dt | J·s (same units as ℏ) |
| L | Lagrangian, L = T − V = ½mẋ² − V(x) | J |
| ℏ | Reduced Planck constant, h/2π | 1.055 × 10⁻³⁴ J·s |
| ∫ Dx(t) | Functional (path) integral over all paths with fixed endpoints | — |
| ψ(x, t) | Wavefunction; propagates via ψ(b) = ∫ K(b,a) ψ(a) dx_a | m⁻¹ᐟ² (1D) |
Because S has units of J·s exactly matching ℏ, the ratio S/ℏ is dimensionless — a pure angle in radians. That is what makes e^(iS/ℏ) a legitimate phase.
Why the classical path wins: stationary phase
Here is the beautiful part. For a baseball, the action of the actual trajectory is on the order of joule-seconds — say S ~ 1 J·s. Divide by ℏ ~ 10⁻³⁴ J·s and you get S/ℏ ~ 10³⁴ radians. Nudge the path a hair and S changes by a tiny amount — but a tiny amount times 10³⁴ is still an enormous number of radians, so the phase e^(iS/ℏ) whirls around the complex circle countless times. Neighbouring paths therefore point in random directions and cancel.
The single exception is near the path where the action is stationary:
δS = 0 (first variation vanishes → Euler–Lagrange equations)
There, to first order, varying the path does not change S, so neighbouring paths share nearly the same phase and add constructively. That stationary path is exactly the classical trajectory picked out by the principle of least (stationary) action. So classical mechanics is not overthrown by quantum mechanics — it emerges as the ℏ → 0 limit, where only the constructively-interfering neighbourhood of the classical path survives. The width of that surviving band scales as √ℏ, which is why quantum "fuzz" is invisible for macroscopic S.
Worked example: the free-particle propagator
For a free particle (V = 0) in one dimension the path integral can be done in closed form because the action is quadratic and the Gaussian integrals converge. The result is one of the cleanest formulas in quantum mechanics:
K(x_b, t; x_a, 0) = √( m / (2πiℏt) ) · exp( i m (x_b − x_a)² / (2ℏt) )
Read off the physics: the phase is exactly the classical action of a free particle covering distance (x_b − x_a) in time t, namely S_cl = m(x_b − x_a)²/2t. Only the classical action appears in the exponent — for quadratic actions the fluctuations contribute only the prefactor √(m/2πiℏt). The 1/√t spreading is the free-particle wavepacket dispersing. For a harmonic oscillator the same method gives K ∝ exp(iS_cl/ℏ) with S_cl = (mω/2sin ωT)[(x_a²+x_b²)cos ωT − 2x_a x_b], again just the classical action times a fluctuation prefactor.
Deriving the Schrödinger equation from the path integral
Feynman's 1948 paper shows the formulations are equivalent by propagating ψ over one infinitesimal slice of time ε. Over that slice,
ψ(x, t + ε) = ∫ K_ε(x, y) ψ(y, t) dy, K_ε ≈ A · exp( (iε/ℏ) [ (m/2)((x−y)/ε)² − V(x) ] )
The kinetic phase (im/2ℏε)(x−y)² oscillates so fast that only y within √(ℏε/m) of x contributes. Set η = y − x, expand ψ(y, t) = ψ(x, t) + η ψ' + ½η²ψ'' , and evaluate the two Gaussian moments ∫e^(imη²/2ℏε)dη = √(2πiℏε/m) and ∫η²e^(imη²/2ℏε)dη = (iℏε/m)·√(2πiℏε/m). Fixing the normalization A = √(m/2πiℏε), matching the O(ε⁰) term, and collecting the O(ε¹) terms gives
iℏ ∂ψ/∂t = − (ℏ²/2m) ∂²ψ/∂x² + V(x) ψ
— the time-dependent Schrödinger equation. The ∂²/∂x² term arises directly from the Gaussian spread η² ~ ℏε/m of the kinetic phase. This is the sense in which the path integral is quantum mechanics, not an approximation to it.
The double slit, re-read as a sum over paths
The path integral gives the double-slit experiment its cleanest reading. The electron does not "go through" one slit — the amplitude at the screen is the sum over all paths, and the paths through slit 1 and slit 2 are simply the two dominant families. Their actions differ by the extra path length, so their phases differ; where the path-length difference is an integer number of de Broglie wavelengths λ = h/p the two amplitudes add (bright fringe) and where it is a half-integer they cancel (dark fringe). The fringe spacing on a screen a distance L behind slits separated by d is Δy = λL/d — identical to the wave-optics answer. Open a third slit and you add a third path family; the machinery is unchanged. Feynman called this "the only mystery" of quantum mechanics, and the path integral turns the mystery into a bookkeeping rule: add the amplitudes, then square.
From particle to field: why QFT is built on it
Replace the particle's coordinate x(t) by a whole field configuration φ(x) defined at every point of spacetime, and the sum over paths becomes a functional integral over all field configurations:
Z = ∫ Dφ exp( (i/ℏ) S[φ] ), S[φ] = ∫ d⁴x ℒ(φ, ∂φ)
This generating functional Z produces every correlation function, and expanding it in the coupling constant generates Feynman diagrams order by order. Its advantages are why it dominates modern high-energy physics: Lorentz invariance and gauge symmetry are manifest in the action; particle creation and annihilation are automatic; gauge fixing has a clean treatment (Faddeev–Popov, BRST). Rotate time to imaginary values, t → −iτ (a Wick rotation), and the oscillating weight e^(iS/ℏ) becomes a real, positive Boltzmann weight e^(−S_E/ℏ) — turning Z into the partition function of statistical mechanics. That single move enables lattice QCD, the renormalization group, and the whole bridge between quantum field theory and critical phenomena.
Three equivalent pictures of quantum mechanics
| Formulation | Central object | Dynamics | Best for |
|---|---|---|---|
| Schrödinger (wave, 1926) | Wavefunction ψ(x, t) | iℏ ∂ψ/∂t = Ĥψ | Bound states, spectra, intuition |
| Heisenberg (matrix, 1925) | Operators Â(t) | dÂ/dt = (i/ℏ)[Ĥ, Â] | Symmetries, algebra, spin |
| Feynman (path integral, 1948) | Propagator K = ∫ Dx e^(iS/ℏ) | Sum over all histories | Classical limit, QFT, gauge theory, lattice |
All three give identical predictions; Dirac's 1933 note that the amplitude "corresponds to" e^(iS/ℏ) planted the seed Feynman turned into a full formulation in his Princeton thesis and the 1948 Reviews of Modern Physics paper.
Common misconceptions
- "The particle actually takes all the paths." The paths are a calculational device, not observable trajectories. Measuring which path is taken destroys the interference. Only the summed amplitude — and its squared magnitude — is physical.
- "Only the classical path matters." It dominates when S ≫ ℏ, but for a quantum system all paths matter; the near-classical band has finite width ~√ℏ, and away from the classical limit the "off-shell" paths carry the interference.
- "The paths are smooth curves." The dominant contributing paths are nowhere differentiable and fractal-like, with |Δx| ~ √Δt, so their velocity diverges and their length is infinite. They are not classical trajectories with wiggles.
- "e^(iS/ℏ) can be tweaked to any weight." Every path has amplitude of magnitude exactly 1; only the phase varies. Weighting by e^(−S) instead of e^(iS/ℏ) is the Euclidean (Wick-rotated) theory, a different setup used for statistical mechanics and convergence.
- "Using Celsius, or forgetting the units of S." S/ℏ must be dimensionless. If you drop the ℏ or use action not in J·s, the phase is meaningless. In natural units ℏ = 1 and the exponent is just iS.
- "The path integral needs an interpretation of measurement." It is agnostic: it reproduces the Born rule for probabilities but says nothing extra about collapse. It is compatible with Copenhagen, many-worlds, or Bohmian readings alike.
Frequently asked questions
What is the path integral formulation in simple terms?
To find the quantum amplitude for a particle to go from point A to point B, you don't pick one trajectory — you add up a complex number for every possible path connecting them, including absurd ones that loop, zigzag, or momentarily exceed light speed. Each path contributes a phase e^(iS/ℏ), where S is the classical action ∫L dt of that path and ℏ = 1.055 × 10⁻³⁴ J·s. The probability of arriving at B is the squared magnitude of that total sum. It is exactly equivalent to Schrödinger's wave mechanics and Heisenberg's matrix mechanics, just written as a sum over histories.
Why does the classical path dominate the sum over all paths?
Because of stationary phase. For a macroscopic object the action S is enormous compared to ℏ, so S/ℏ is a gigantic number and the phase e^(iS/ℏ) spins wildly as you vary the path — neighbouring paths carry wildly different phases and cancel. The one place cancellation fails is near the path where the action is stationary, δS = 0, because there neighbouring paths share nearly the same phase and add constructively. That stationary path is precisely the classical trajectory of the principle of least action. So classical mechanics is the ℏ → 0 limit of the path integral.
What is the propagator in the path integral?
The propagator K(b, a) = ⟨x_b, t_b | x_a, t_a⟩ is the total amplitude to go from (x_a, t_a) to (x_b, t_b). Feynman wrote it as K = ∫ Dx(t) exp(iS[x]/ℏ), a functional integral over all paths x(t) with the given endpoints. It is the position-space matrix element of the time-evolution operator e^(-iĤt/ℏ), and it is the Green's function of the Schrödinger equation. Given K, any wavefunction propagates by ψ(x_b, t_b) = ∫ K(b, a) ψ(x_a, t_a) dx_a. For a free particle in 1D, K = √(m / 2πiℏt) · exp(im(x_b − x_a)²/2ℏt).
How does the path integral recover the Schrödinger equation?
You propagate the wavefunction over an infinitesimal time slice ε. The exponent (iε/ℏ)L contains the kinetic term (m/2ε)(x_b − x_a)², which forces the important contributions to come from x_b ≈ x_a with a spread of order √(ℏε/m). Expanding ψ to first order in ε and second order in the displacement, doing the resulting Gaussian integrals, and matching powers of ε yields iℏ ∂ψ/∂t = −(ℏ²/2m)∂²ψ/∂x² + Vψ — the time-dependent Schrödinger equation. Feynman gives this derivation in his 1948 paper; the ∂²/∂x² arises directly from the Gaussian spread of the kinetic phase.
How does the path integral reinterpret the double-slit experiment?
In the sum-over-histories view the electron does not go through one slit or the other — the amplitude at the screen is the sum over every path, and the two paths through the two slits are just the two dominant families. Their actions differ, so their phases e^(iS/ℏ) differ, and where the path-length difference is a whole number of de Broglie wavelengths the amplitudes add (bright fringe) and where it is a half-wavelength they cancel (dark fringe). Adding a third or fourth slit simply adds more path families to the sum. Feynman called the double slit the single experiment that contains 'the only mystery' of quantum mechanics, and the path integral makes the interference a bookkeeping statement about summing amplitudes.
Why is the path integral the foundation of quantum field theory?
In field theory the 'coordinate' is a whole field configuration φ(x) at each spacetime point, and the sum over paths becomes a functional integral over all field configurations: Z = ∫ Dφ exp(iS[φ]/ℏ), with S the field action. This generating functional yields correlation functions and, expanded in the coupling, produces Feynman diagrams term by term. It makes Lorentz invariance and gauge symmetry manifest, treats particle creation and annihilation naturally, and — after a Wick rotation t → −iτ giving weight e^(−S_E/ℏ) — becomes the partition function of statistical mechanics, enabling lattice QCD and the renormalization group. Modern gauge theory (Faddeev–Popov, BRST) is built on it.
Are the paths in the path integral real physical trajectories?
No. The paths are a calculational device, not observable trajectories. The dominant paths are nowhere-differentiable and fractal-like: a typical contributing path has |Δx| ~ √Δt, so its 'velocity' Δx/Δt diverges as the time step shrinks and its length is infinite. Because measuring which path the particle took would collapse the state and destroy the interference, no experiment can single out one path. The path integral is agnostic about interpretation — it gives the same predictions as Copenhagen or many-worlds; only the total summed amplitude, and its squared magnitude as a probability, is physical.